Arrange given numbers to form the smallest number

Given an array arr[] of integer elements, the task is to arrange them in such a way that these numbers form the smallest possible number.
For example, if the given array is {5, 6, 2, 9, 21, 1} then the arrangement will be 1212569.
Examples:
Input: arr[] = {5, 6, 2, 9, 21, 1}
Output: 1212569Input: arr[] = {1, 2, 1, 12, 33, 211, 50}
Output: 111221123350
Approach: If all the given numbers are of at most one digit then the simple approach is sorting all numbers in ascending order. But if there is some number which have more than a single-digit then this approach will not work.
Therefore, we have to sort the array by comparing any two elements in the following way:
If the elements are A and B, then compare (A + B) with (B + A) where + represents concatenation.
Below is the implementation of the above approach:
C++
// C++ implementation of the approach#include <algorithm>#include <iostream>using namespace std;// Utility function to print// the contents of an arrayvoid printArr(int arr[], int n){ for (int i = 0; i < n; i++) cout << arr[i];}// A comparison function that return true// if 'AB' is smaller than 'BA' when// we concatenate two numbers 'A' and 'B'// For example, it will return true if// we pass 12 and 24 as arguments.// This function will be used by sort() functionbool compare(int num1, int num2){ // to_string function is predefined function // to convert a number in string // Convert first number to string format string A = to_string(num1); // Convert second number to string format string B = to_string(num2); // Check if 'AB' is smaller or 'BA' // and return bool value since // comparison operator '<=' returns // true or false return (A + B) <= (B + A);}// Function to print the arrangement// with the smallest valuevoid printSmallest(int N, int arr[]){ // If we pass the name of the comparison // function it will sort the array // according to the compare function sort(arr, arr + N, compare); // Print the sorted array printArr(arr, N);}// Driver codeint main(){ int arr[] = { 5, 6, 2, 9, 21, 1 }; int N = sizeof(arr) / sizeof(arr[0]); printSmallest(N, arr); return 0;} |
Java
// Java implementation of the approach class GFG{ // Utility function to print // the contents of an array public static void printArr(int[] arr, int n) { for (int i = 0; i < n; i++) System.out.print(arr[i]); } // A comparison function that return negative // if 'AB' is smaller than 'BA' when // we concatenate two numbers 'A' and 'B' // For example, it will return negative value if // we pass 12 and 24 as arguments. // This function will be used during sort public static int compare(int num1, int num2) { // toString function is predefined function // to convert a number in string // Convert first number to string format String A = Integer.toString(num1); // Convert second number to string format String B = Integer.toString(num2); // Check if 'AB' is smaller or 'BA' // and return integer value return (A+B).compareTo(B+A); } // Function to print the arrangement // with the smallest value public static void printSmallest(int N, int[] arr) { // Sort using compare function which // is defined above for (int i = 0; i < N; i++) { for (int j = i + 1; j < N; j++) { if (compare(arr[i], arr[j]) > 0) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } // Print the sorted array printArr(arr, N); } // Driver code public static void main(String[] args) { int[] arr = { 5, 6, 2, 9, 21, 1 }; int N = arr.length; printSmallest(N, arr); }}// This code is contributed by// sanjeev2552 |
Python3
# Python3 implementation of the approach# Utility function to print# the contents of an arraydef printArr(arr, n): for i in range(0, n): print(arr[i], end = "")# A comparison function that return true# if 'AB' is smaller than 'BA' when# we concatenate two numbers 'A' and 'B'# For example, it will return true if# we pass 12 and 24 as arguments.# This function will be used by sort() functiondef compare(num1, num2): # Convert first number to string format A = str(num1) # Convert second number to string format B = str(num2) # Check if 'AB' is smaller or 'BA' # and return bool value since # comparison operator '<=' returns # true or false return int(A + B) <= int(B + A) def sort(arr): for i in range(len(arr)): for j in range(i + 1, len(arr)): if compare(arr[i], arr[j]) == False: arr[i], arr[j] = arr[j], arr[i]# Function to print the arrangement# with the smallest valuedef printSmallest(N, arr): # If we pass the name of the comparison # function it will sort the array # according to the compare function sort(arr) # Print the sorted array printArr(arr, N)# Driver codeif __name__ == "__main__": arr = [5, 6, 2, 9, 21, 1] N = len(arr) printSmallest(N, arr)# This code is contributed by Rituraj Jain |
C#
// C# implementation for above approachusing System;class GFG{ // Utility function to print // the contents of an array public static void printArr(int[] arr, int n) { for (int i = 0; i < n; i++) Console.Write(arr[i]); } // A comparison function that return negative // if 'AB' is smaller than 'BA' when // we concatenate two numbers 'A' and 'B' // For example, it will return negative value if // we pass 12 and 24 as arguments. // This function will be used during sort public static int compare(int num1, int num2) { // toString function is predefined function // to convert a number in string // Convert first number to string format String A = num1.ToString(); // Convert second number to string format String B = num2.ToString(); // Check if 'AB' is smaller or 'BA' // and return integer value return (A+B).CompareTo(B+A); } // Function to print the arrangement // with the smallest value public static void printSmallest(int N, int[] arr) { // Sort using compare function which // is defined above for (int i = 0; i < N; i++) { for (int j = i + 1; j < N; j++) { if (compare(arr[i], arr[j]) > 0) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } // Print the sorted array printArr(arr, N); } // Driver code public static void Main(String[] args) { int[] arr = { 5, 6, 2, 9, 21, 1 }; int N = arr.Length; printSmallest(N, arr); }}// This code is contributed by Rajput-Ji |
PHP
<?php// PHP implementation of the approach // Utility function to print // the contents of an array function printArr($arr, $n) { for ($i = 0; $i < $n; $i++) echo $arr[$i]; } // A comparison function that return true // if 'AB' is smaller than 'BA' when // we concatenate two numbers 'A' and 'B' // For example, it will return true if // we pass 12 and 24 as arguments. // This function will be used by sort() function function compare($num1, $num2) { // to_string function is predefined function // to convert a number in string // Convert first number to string format $A = (string)$num1 ; // Convert second number to string format $B = (string)$num2 ; // Check if 'AB' is smaller or 'BA' // and return bool value since // comparison operator '<=' returns // true or false if((int)($A . $B) <= (int)($B . $A)) { return true; } else return false;} function sort_arr($arr){ for ($i = 0; $i < count($arr) ; $i++) { for ($j = $i + 1;$j < count($arr) ; $j++) { if (compare($arr[$i], $arr[$j]) == false) { $temp = $arr[$i] ; $arr[$i] = $arr[$j] ; $arr[$j] = $temp ; } } } return $arr ; }// Function to print the arrangement // with the smallest value function printSmallest($N, $arr) { // If we pass the name of the comparison // function it will sort the array // according to the compare function $arr = sort_arr($arr); // Print the sorted array printArr($arr, $N); } // Driver code $arr = array(5, 6, 2, 9, 21, 1 ); $N = count($arr); printSmallest($N, $arr); // This code is contributed by Ryuga?> |
Javascript
<script> // Javascript implementation of the approach // Utility function to print // the contents of an array function printArr(arr,n) { for (let i = 0; i < n; i++) document.write(arr[i]); } // A comparison function that return true // if 'AB' is smaller than 'BA' when // we concatenate two numbers 'A' and 'B' // For example, it will return true if // we pass 12 and 24 as arguments. // This function will be used by sort() function function compare(num1,num2) { // to_string function is predefined function // to convert a number in string // Convert first number to string format let A = num1.toString(); // Convert second number to string format let B = num2.toString(); // Check if 'AB' is smaller or 'BA' // and return bool value since // comparison operator '<=' returns // true or false return (A + B).localeCompare(B + A); } // Function to print the arrangement // with the smallest value function printSmallest(N,arr) { // If we pass the name of the comparison // function it will sort the array // according to the compare function // Sort using compare function which // is defined above for (let i = 0; i < N; i++) { for (let j = i + 1; j < N; j++) { if (compare(arr[i], arr[j]) > 0) { let temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } // Print the sorted array printArr(arr,N); } // Driver code let arr = [ 5, 6, 2, 9, 21, 1 ]; let N = arr.length; printSmallest(N,arr);</script> |
1212569
Time Complexity: O(nlogn)
Auxiliary Space: O(1)
Approach 2: Implementing a custom quicksort algorithm
Another way to solve the problem is to implement a custom quicksort algorithm that uses the same comparison function as in approach 1. The quicksort algorithm recursively partitions the array into two subarrays based on the comparison function, and then combines the sorted subarrays to form the final result.
C++
#include <iostream>#include <vector>#include <string>using namespace std;bool compare(string a, string b) { return (a+b) < (b+a);}int partition(vector<string>& arr, int low, int high) { string pivot = arr[high]; int i = low - 1; for (int j = low; j <= high - 1; j++) { if (compare(arr[j], pivot)) { i++; swap(arr[i], arr[j]); } } swap(arr[i+1], arr[high]); return i+1;}void quicksort(vector<string>& arr, int low, int high) { if (low < high) { int pi = partition(arr, low, high); quicksort(arr, low, pi - 1); quicksort(arr, pi + 1, high); }}string smallestNumber(vector<int>& nums) { vector<string> numStrs; for (int num : nums) { numStrs.push_back(to_string(num)); } quicksort(numStrs, 0, numStrs.size()-1); string result = ""; for (string numStr : numStrs) { result += numStr; } return result;}int main() { vector<int> nums = { 5, 6, 2, 9, 21, 1 }; cout << smallestNumber(nums) << endl; // Output: 3033459 return 0;} |
1212569
Time Complexity: O(nlogn)
Auxiliary Space: O(n)
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