XOR and OR of all N-digit palindrome number

Given an integer N. The task is to find the XOR and OR of all N digit palindromic numbers.
Examples
Input: 3
Output: XOR = 714 and OR = 1023
Input: 4
Output: XOR = 4606 and OR = 16383
Approach:
- Find the starting and ending number of N-digit palindromic number by:
starting number = pow(10, n - 1) ending number = pow(10, n) - 1
- Iterate over starting number till ending number and check whether that number is palindromic or not.
- If the number is palindromic, then take XOR and OR of that number separately.
- Else proceed for next iteration and print the value of XOR and OR after all iterations.
Below is the implementation of the above approach:
C++
// C++ program to find the XOR// and OR of all palindrome numbers// of N digits#include <bits/stdc++.h>using namespace std;// Function to check if a number// is palindrome or notbool ispalin(int num){ // Convert the num n to string string s = to_string(num); int st = 0, ed = s.size() - 1; // Iterate over string to // check whether it is // palindromic or not while (st <= ed) { if (s[st] != s[ed]) return false; st++; ed--; } return true;}// Function to find XOR of all// N-digits palindrome numbervoid CalculateXORandOR(int n){ // To store the XOR and OR of all // palindromic number int CalculateXOR = 0; int CalculateOR = 0; // Starting N-digit // palindromic number int start = pow(10, n - 1); // Ending N-digit // palindromic number int end = pow(10, n) - 1; // Iterate over starting and /// ending number for (int i = start; i <= end; i++) { // To check if i is // palindromic or not if (ispalin(i)) { CalculateXOR = CalculateXOR ^ i; CalculateOR = CalculateOR | i; } } // Print the XOR and OR of all // palindromic number cout << "XOR = " << CalculateXOR; cout << " OR = " << CalculateOR;}// Driver Codeint main(){ int n = 4; CalculateXORandOR(n); return 0;} |
Java
// Java program to find the XOR// and OR of all palindrome numbers// of N digitsclass GFG{// Function to check if a number// is palindrome or notstatic boolean ispalin(int num){ // Convert the num n to string String s = Integer.toString(num); int st = 0, ed = s.length() - 1; // Iterate over string to // check whether it is // palindromic or not while (st <= ed) { if (s.charAt(st) != s.charAt(ed)) return false; st++; ed--; } return true;}// Function to find XOR of all// N-digits palindrome numberstatic void CalculateXORandOR(int n){ // To store the XOR and OR of all // palindromic number int CalculateXOR = 0; int CalculateOR = 0; // Starting N-digit // palindromic number int start = (int)Math.pow(10, n - 1); // Ending N-digit // palindromic number int end = (int)Math.pow(10, n) - 1; // Iterate over starting and /// ending number for (int i = start; i <= end; i++) { // To check if i is // palindromic or not if (ispalin(i)) { CalculateXOR = CalculateXOR ^ i; CalculateOR = CalculateOR | i; } } // Print the XOR and OR of all // palindromic number System.out.print("XOR = " + CalculateXOR); System.out.println(" OR = " + CalculateOR);}// Driver Codepublic static void main (String[] args) { int n = 4; CalculateXORandOR(n);}}// This code is contributed by AnkitRai01 |
Python3
# Python3 program to find the XOR # and OR of all palindrome numbers # of N digits # Function to check if a number # is palindrome or not def ispalin(num) : # Convert the num n to string s = str(num); st = 0; ed = len(s) - 1; # Iterate over string to # check whether it is # palindromic or not while (st <= ed) : if (s[st] != s[ed]) : return False; st += 1; ed -= 1; return True; # Function to find XOR of all # N-digits palindrome number def CalculateXORandOR(n) : # To store the XOR and OR of all # palindromic number CalculateXOR = 0; CalculateOR = 0; # Starting N-digit # palindromic number start = 10 ** (n - 1); # Ending N-digit # palindromic number end = (10**n) - 1; # Iterate over starting and # ending number for i in range( start, end + 1) : # To check if i is # palindromic or not if (ispalin(i)) : CalculateXOR = CalculateXOR ^ i; CalculateOR = CalculateOR | i; # Print the XOR and OR of all # palindromic number print("XOR =", CalculateXOR,end = " "); print("OR = ", CalculateOR); # Driver Code if __name__ == "__main__" : n = 4; CalculateXORandOR(n); # This code is contributed by AnkitRai01 |
C#
// C# program to find the XOR// and OR of all palindrome numbers// of N digitsusing System;class GFG{// Function to check if a number// is palindrome or notstatic bool ispalin(int num){ // Convert the num n to string string s = num.ToString(); int st = 0; int ed = s.Length - 1; // Iterate over string to // check whether it is // palindromic or not while (st <= ed) { if (s[st] != s[ed]) return false; st++; ed--; } return true;}// Function to find XOR of all// N-digits palindrome numberstatic void CalculateXORandOR(int n){ // To store the XOR and OR of all // palindromic number int CalculateXOR = 0; int CalculateOR = 0; // Starting N-digit // palindromic number int start = (int)Math.Pow(10, n - 1); // Ending N-digit // palindromic number int end = (int)Math.Pow(10, n) - 1; // Iterate over starting and /// ending number for (int i = start; i <= end; i++) { // To check if i is // palindromic or not if (ispalin(i)) { CalculateXOR = CalculateXOR ^ i; CalculateOR = CalculateOR | i; } } // Print the XOR and OR of all // palindromic number Console.Write("XOR = " + CalculateXOR); Console.WriteLine(" OR = " + CalculateOR);}// Driver Codepublic static void Main (string[] args) { int n = 4; CalculateXORandOR(n);}}// This code is contributed by AnkitRai01 |
Javascript
<script>// Javascript program to find the XOR// and OR of all palindrome numbers// of N digits// Function to check if a number// is palindrome or notfunction ispalin(num){ // Convert the num n to string let s = num.toString(); let st = 0, ed = s.length - 1; // Iterate over string to // check whether it is // palindromic or not while (st <= ed) { if (s[st] != s[ed]) return false; st++; ed--; } return true;}// Function to find XOR of all// N-digits palindrome numberfunction CalculateXORandOR(n){ // To store the XOR and OR of all // palindromic number let CalculateXOR = 0; let CalculateOR = 0; // Starting N-digit // palindromic number let start = Math.pow(10, n - 1); // Ending N-digit // palindromic number let end = Math.pow(10, n) - 1; // Iterate over starting and /// ending number for (let i = start; i <= end; i++) { // To check if i is // palindromic or not if (ispalin(i)) { CalculateXOR = CalculateXOR ^ i; CalculateOR = CalculateOR | i; } } // Print the XOR and OR of all // palindromic number document.write("XOR = " + CalculateXOR); document.write(" OR = " + CalculateOR);}// Driver Code let n = 4; CalculateXORandOR(n);</script> |
Output:
XOR = 4606 OR = 16383
Time Complexity: O(10n)
Auxiliary Space: O(1)
Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 zambiatek!
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 zambiatek!



