Python | sympy.is_comparable() method
With the help of sympy.is_comparable() method, we can compute the real number with precision and return True if computed value is real with precision by using sympy.is_comparable() method.
Syntax :
sympy.is_comparable()
Return : Return boolean value if real number is computed.
Example #1 :
In this example we can see that by using sympy.is_comparable() method, we are able to evaluate the expression and if computed value is real with precision it will return True else False.
# import sympy from sympy import *   x, y, z = symbols('x y z')   # Use sympy.is_comparable() method gfg = (3 * x + 2 * tan(y + I * pi) + log(2 * x)).is_comparable     print(gfg) |
Output :
False
Example #2 :
# import sympy from sympy import *   x, y, z = symbols('x y z')   # Use sympy.is_comparable() method gfg = (pi / 2).is_comparable     print(gfg) |
Output :
True
