Python | sympy.has() method
With the help of sympy.has() method, we can check if variable is used in that mathematical expression or not and this will return a boolean values by using sympy.has() method.
Syntax :
sympy.has(variable)
Return : Return boolean value i.e True or False.
Example #1 :
In this example we can see that by using sympy.has() method, we are able to check the variable is used in the mathematical expression or not.
# import sympy from sympy import * x, y, z = symbols('x y z') # Use sympy.has() method gfg = (3 * x + 2 * tan(y + I * pi) + log(2 * x)).has(x) print(gfg) |
Output :
True
Example #2 :
# import sympy from sympy import * x, y, z = symbols('x y z') # Use sympy.has() method gfg = (3 * sin(x) + 2 * tan(y + I * pi)).has(z) print(gfg) |
Output :
False
