D3.js | d3.timeMonths() Function

The d3.timeMonths() function in D3.js is used to return all the months with date in the given range of start and end date.
Syntax:
d3.timeMonths(start, end, step);
Parameters: This function accept three parameters which are given below:
- Start: This parameter holds the given start date.
- end: This parameter holds the given end date.
- step: It is optional parameter which holds the value used to skip the months.
Return Value: This function returns all the possible months in the given range.
Below programs illustrate the d3.timeMonths() function in D3.js:
Example 1:
| <!DOCTYPE html> <html>    <head>       <title>           D3.js | d3.timeMonths() Function       </title>   Â      <script src =       </script>      </head>   Â   <body>         Â      <script>         Â         // Initialising start and end date          varstart = newDate(2015, 01, 01);          varend = newDate(2015, 05, 01);           Â         // Calling the timeMonths() function          // without step value          vara = d3.timeMonths(start, end);           Â         // Getting the months values          console.log(a);       </script>    </body> </html>  | 
Output:
["2015-01-31T18:30:00.000Z", "2015-02-28T18:30:00.000Z", "2015-03-31T18:30:00.000Z", "2015-04-30T18:30:00.000Z"]
Example 2:
| <!DOCTYPE html> <html>    <head>       <script src =       </script>  Â      <title>           D3.js | d3.timeMonths() Function       </title>       </head>   Â   <body>         Â      <script>         Â         // Initialising start and end date          varstart = newDate(2015, 01, 01);          varend = newDate(2015, 05, 01);           Â         // Calling the timeMonths() function          // with step value          vara = d3.timeMonths(start, end, 2);           Â         // Getting the months values          console.log(a);       </script>    </body> </html>  | 
Output:
["2015-01-31T18:30:00.000Z", "2015-03-31T18:30:00.000Z"]
Reference: https://devdocs.io/d3~5/d3-time#timeMonths
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