D3.js | color.displayable() Function

0 0 1 minute read

The color.displayable() function in D3.js is used to return true if the color is displayable otherwise false.

Syntax:

color.displayable()

Parameters: This function does not accept any parameters.

Return Value: This function returns true if the color is displayable otherwise false.

Below program illustrate the color.displayable() function in D3.js:

Example:

<!DOCTYPE html> 
<html> 
  
<head> 
    <title> 
      color.displayable() function
  </title> 
  
    <script src= 
'https://d3js.org/d3.v4.min.js'> 
  </script> 
</head> 
  
<body> 
    <script> 
        // Calling the d3.color() function 
        // with some parameters 
        var color1 = d3.color("red"); 
        var color2 = d3.color("green"); 
        var color3 = d3.color("blue"); 
  
        // Calling the color.displayable() function 
        var A = color1.displayable(); 
        var B = color2.displayable(); 
        var C = color3.displayable(); 
  
        // Getting the value true or false 
        console.log(A); 
        console.log(B); 
        console.log(C); 
    </script> 
</body> 
  
</html> 

Output:

true
true
true

Ref: https://devdocs.io/d3~5/d3-color#color_displayable

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