Python | Sympy Plane.projection_line() method
In Sympy, the function
Plane.projection_line() is used to project the given line onto the given plane through the normal plane containing the line.
Syntax: Plane.projection_line(line) Parameters: line: LinearEntity or LinearEntity3D Returns: Point3D, Line3D, Ray3D or Segment3D
Example #1:
# import sympy and Plane, Line, Line3D, Point, Point3D from sympy import Plane, Line, Line3D, Point, Point3D p = Line(Point(1, 2), Point(2, 3)) # using Plane() p1 = Plane(Point3D(1, 2, 3), normal_vector =(1, 0, 1)) # using projection_line() projectionLine = p1.projection_line(p) print(projectionLine) |
Output:
Line3D(Point3D(5/2, 2, 3/2), Point3D(3, 3, 1))
Example #2:
# import sympy and Plane, Line, Line3D, Point, Point3D from sympy import Plane, Line, Line3D, Point, Point3D p = Line3D(Point3D(1, 2, 3), Point(0, 0, 0)) # using Plane() p2 = Plane(Point3D(1, 1, 1), normal_vector =(0, 0, 0)) # using projection_line() projectionLine = p2.projection_line(p) print(projectionLine) |
Output:
Line3D(Point3D(1, 2, 3), Point3D(2, 0, 2))
