Python3 Program to Find Lexicographically smallest rotated sequence | Set 2

Write code to find lexicographic minimum in a circular array, e.g. for the array BCABDADAB, the lexicographic minimum is ABBCABDAD
Input Constraint: 1 < n < 1000 
Examples: 
 
Input: GEEKSQUIZ Output: EEKSQUIZG Input: GFG Output: FGG Input : CAPABCQ Output : ABCQCAP
We have discussed a O(n2Logn) solution in Lexicographically minimum string rotation | Set 1. Here we need to find the starting index of minimum rotation and then print the rotation.
 
1) Initially assume 0 to be current min 
   starting index.
2) Loop through i = 1 to n-1.
   a) For each i compare sequence starting 
      at i with current min starting index
   b) If sequence starting at i is lexicographically 
      smaller, update current min starting 
      index.
Here is pseudo-code for algorithm 
 
function findIndexForSmallestSequence(S, n):
    result = 0
    for i = 1:n-1
        if (sequence beginning at i < 
               sequence beginning at result)
            result = i
        end if
    end for
    return result
Here is implementation of above algorithm. 
 
Python 3
# Python 3 program to find lexicographically # smallest sequence with rotations.   # Function to compare lexicographically # two sequence with different starting # indexes. It returns true if sequence # beginning with y is lexicographically # greater. import copy     def printSmallestSequence(s):     m = copy.copy(s)     for i in range(len(s) - 1):           if m > s[i:] + s[:i]:             m = s[i:] + s[:i]       return m   #Driver Code if __name__ == '__main__':       st = 'DCACBCAA'    print(printSmallestSequence(st))     # This code is contributed by Koushik Reddy B  | 
Output: 
 
AADCACBC
Time Complexity : O(n^2) 
Auxiliary Space : O(1)
Please refer complete article on Lexicographically smallest rotated sequence | Set 2 for more details!
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