Time Difference between given times in HH:MM:SS format

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Given 2 times ‘st‘ and ‘et‘ in HH: MM: SS format. The task is to print the time difference between st and et in HH:MM: SS format

Examples:

Input: st = 13:50:45, et = 14:55:50
Output: 01:05:05
Explanation: The time gap is 1 hour 5 minutes and 5 seconds.

Input: st = 12:00:00, et = 24:00:00
Output: 12:00:00
Explanation: The time gap is of 12 hours.

Approach: The task can be solved by converting both the given times in ‘seconds‘ format & then find the absolute difference between the two. Then convert this absolute difference into HH:MM: SS format
Below is the implementation of the above approach:

C++

// C++ program for the above approach
#include <bits/stdc++.h>
using namespace std;
 
class Solution {
public:
    // Function to find the time difference
    long long int getTimeInSeconds(string str)
    {
 
        vector<int> curr_time;
        istringstream ss(str);
        string token;
 
        while (getline(ss, token, ':')) {
 
            curr_time.push_back(stoi(token));
        }
 
        long long int t = curr_time[0] * 60 * 60
                          + curr_time[1] * 60
                          + curr_time[2];
 
        return t;
    }
 
    // Function to convert seconds back to hh::mm:ss
    // format
    string convertSecToTime(long long int t)
    {
        int hours = t / 3600;
        string hh = hours < 10 ? "0" + to_string(hours)
                               : to_string(hours);
        int min = (t % 3600) / 60;
        string mm = min < 10 ? "0" + to_string(min)
                             : to_string(min);
        int sec = ((t % 3600) % 60);
        string ss = sec < 10 ? "0" + to_string(sec)
                             : to_string(sec);
        string ans = hh + ":" + mm + ":" + ss;
        return ans;
    }
 
    // Function to find the time gap
    string timeGap(string st, string et)
    {
 
        long long int t1 = getTimeInSeconds(st);
        long long int t2 = getTimeInSeconds(et);
 
        long long int time_diff
            = (t1 - t2 < 0) ? t2 - t1 : t1 - t2;
 
        return convertSecToTime(time_diff);
    }
};
 
// Driver Code
int main()
{
 
    string st = "13:50:45", et = "14:55:50";
    Solution ob;
    cout << ob.timeGap(st, et) << "\n";
 
    return 0;
}

Java

// Java program for the above approach
class GFG {
 
    // Function to find the time difference
    static int getTimeInSeconds(String str) {
 
        String[] curr_time = str.split(":");
        int t = Integer.parseInt(curr_time[0]) * 60 * 60 + Integer.parseInt(curr_time[1]) * 60
                + Integer.parseInt(curr_time[2]);
 
        return t;
    }
 
    // Function to convert seconds back to hh::mm:ss
    // format
    static String convertSecToTime(int t) {
        int hours = t / 3600;
        String hh = hours < 10 ? "0" + Integer.toString(hours)
                : Integer.toString(hours);
        int min = (t % 3600) / 60;
        String mm = min < 10 ? "0" + Integer.toString(min)
                : Integer.toString(min);
        int sec = ((t % 3600) % 60);
        String ss = sec < 10 ? "0" + Integer.toString(sec)
                : Integer.toString(sec);
        String ans = hh + ":" + mm + ":" + ss;
        return ans;
    }
 
    // Function to find the time gap
    static String timeGap(String st, String et) {
 
        int t1 = getTimeInSeconds(st);
        int t2 = getTimeInSeconds(et);
 
        int time_diff = (t1 - t2 < 0) ? t2 - t1 : t1 - t2;
 
        return convertSecToTime(time_diff);
    }
 
    // Driver Code
    public static void main(String args[]) {
 
        String st = "13:50:45", et = "14:55:50";
        System.out.println(timeGap(st, et));
    }
}
 
// This code is contributed by saurabh_jaiswal.

Python3

# Python 3 program for the above approach
 
# Function to find the time difference
def getTimeInSeconds(str):
 
    curr_time = str.split(':')
 
    t = (int(curr_time[0]) * 60 * 60
         + int(curr_time[1]) * 60
         + int(curr_time[2]))
 
    return t
 
# Function to convert seconds back to hh::mm:ss
# format
def convertSecToTime(t):
 
    hours = t // 3600
    if hours < 10:
        hh = "0" + str(hours)
    else:
        hh = str(hours)
    min = (t % 3600) // 60
    if min < 10:
        mm = "0" + str(min)
    else:
        mm = str(min)
    sec = ((t % 3600) % 60)
    if sec < 10:
        ss = "0" + str(sec)
    else:
        ss = str(sec)
    ans = hh + ":" + mm + ":" + ss
    return ans
 
# Function to find the time gap
def timeGap(st,  et):
 
    t1 = getTimeInSeconds(st)
    t2 = getTimeInSeconds(et)
 
    if (t1 - t2 < 0):
        time_diff = t2 - t1
    else:
        time_diff = t1 - t2
 
    return convertSecToTime(time_diff)
 
# Driver Code
if __name__ == "__main__":
 
    st = "13:50:45"
    et = "14:55:50"
 
    print(timeGap(st, et))
 
    # This code is contributed by ukasp.

C#

// C# program for the above approach
using System;
using System.Collections.Generic;
public class GFG {
 
    // Function to find the time difference
    static int getTimeInSeconds(String str) {
 
        String[] curr_time = str.Split(':');
        int t = Int32.Parse(curr_time[0]) * 60 * 60 + Int32.Parse(curr_time[1]) * 60
                + Int32.Parse(curr_time[2]);
 
        return t;
    }
 
    // Function to convert seconds back to hh::mm:ss
    // format
    static String convertSecToTime(int t) {
        int hours = t / 3600;
        String hh = hours < 10 ? "0" + hours.ToString()
                : hours.ToString();
        int min = (t % 3600) / 60;
        String mm = min < 10 ? "0" + min.ToString()
                : min.ToString();
        int sec = ((t % 3600) % 60);
        String ss = sec < 10 ? "0" + sec.ToString()
                : sec.ToString();
        String ans = hh + ":" + mm + ":" + ss;
        return ans;
    }
 
    // Function to find the time gap
    static String timeGap(String st, String et) {
 
        int t1 = getTimeInSeconds(st);
        int t2 = getTimeInSeconds(et);
 
        int time_diff = (t1 - t2 < 0) ? t2 - t1 : t1 - t2;
 
        return convertSecToTime(time_diff);
    }
 
    // Driver Code
    public static void Main(String []args) {
 
        String st = "13:50:45", et = "14:55:50";
        Console.WriteLine(timeGap(st, et));
    }
}
 
// This code is contributed by shikhasingrajput

Javascript

<script>
       // JavaScript code for the above approach
 
       // Function to find the time difference
       function getTimeInSeconds(str) {
 
           let curr_time = [];
 
           curr_time = str.split(':')
           for (let i = 0; i < curr_time.length; i++) {
               curr_time[i] = parseInt(curr_time[i]);
           }
 
           let t = curr_time[0] * 60 * 60
               + curr_time[1] * 60
               + curr_time[2];
 
           return t;
       }
 
       // Function to convert seconds back to hh::mm:ss
       // format
       function convertSecToTime(t) {
           let hours = Math.floor(t / 3600);
           let hh = hours < 10 ? "0" + (hours).toString()
               : (hours).toString();
           let min = Math.floor((t % 3600) / 60);
           let mm = min < 10 ? "0" + (min).toString()
               : (min).toString();
           let sec = ((t % 3600) % 60);
           let ss = sec < 10 ? "0" + (sec).toString()
               : (sec).toString();
           let ans = hh + ":" + mm + ":" + ss;
           return ans;
       }
 
       // Function to find the time gap
       function timeGap(st, et) {
 
           let t1 = getTimeInSeconds(st);
           let t2 = getTimeInSeconds(et);
 
           let time_diff
               = (t1 - t2 < 0) ? t2 - t1 : t1 - t2;
 
           return convertSecToTime(time_diff);
       }
 
       // Driver Code
       let st = "13:50:45", et = "14:55:50";
 
       document.write(timeGap(st, et) + '<br>');
 
 // This code is contributed by Potta Lokesh
   </script>

Output

01:05:05

Time complexity: O(1)
Auxiliary Space: O(1)

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