Area of a Square | Using Side, Diagonal and Perimeter

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Given one of the Sides S, Diagonal D, or Perimeter P of the square, the task is to find the area of the square with the given value.

Examples:

Input: S = 5
Output: Area of the square using side = 25

Input: D = 4
Output: Area of the square using diagonal = 8

Input: P = 32
Output: Area of the square using perimeter = 64

Finding Area of Square using its Side

The area of the square of the side S is given by:

Area = Side * Side

Below is the implementation of the above approach:

C++

// C++ program for the above approach
#include <iostream>
using namespace std;
 
// Function to find the area of a square
int areaOfSquare(int S)
{
    // Use above formula
    int area = S * S;
 
    return area;
}
 
// Driver Code
int main()
{
 
    // Given Side of square
    int S = 5;
 
    // Function call
    cout << areaOfSquare(S);
    return 0;
}

Java

// Java program for the above approach
class GFG{
  
// Function to find the area of a square
static int areaOfSquare(int S)
{
    // Use above formula
    int area = S * S;
  
    return area;
}
  
// Driver Code
public static void main(String[] args)
{
  
    // Given Side of square
    int S = 5;
  
    // Function call
    System.out.println(areaOfSquare(S));
}
}
 
// This code is contributed by rock_cool

Python3

# Python3 program for the above approach
 
# Function to find the area of a square
def areaOfSquare(S):
 
    # Use above formula
    area = S * S
 
    return area
 
# Driver Code
if __name__ == '__main__':
 
    # Given Side of square
    S = 5
 
    # Function call
    print(areaOfSquare(S))
 
# This code is contributed by Mohit Kumar

C#

// C# program for the above approach
using System;
class GFG{
   
// Function to find the area of a square
static int areaOfSquare(int S)
{
    // Use above formula
    int area = S * S;
   
    return area;
}
   
// Driver Code
public static void Main(string[] args)
{
   
    // Given Side of square
    int S = 5;
   
    // Function call
    Console.Write(areaOfSquare(S));
}
}
 
// This code is contributed by Ritik Bansal

Javascript

<script>
 
    // Javascript program for the above approach
     
    // Function to find the area of a square
    function areaOfSquare(S)
    {
        // Use above formula
        let area = S * S;
 
        return area;
    }
 
    // Given Side of square
    let S = 5;
  
    // Function call
    document.write(areaOfSquare(S));
     
    // This code is contributed by divyeshrabadiya07.
     
</script>

Output:

Time Complexity: O(1)
Auxiliary Space: O(1)

Finding Area of Square using its Diagonal

The Area of the square of given side S is given by:

Area = S * S …(1)

The relation between Side S and Diagonal D is given by:

$D = \sqrt{2}*S$

…(2)

Substituting the value of S from Equation (2) in Equation (1), we have:

$Area = (\frac{D}{\sqrt{2}})^{2} = \frac{D*D}{2}$

Below is the implementation of the above approach:

C++

// C++ program for the above approach
#include <iostream>
using namespace std;
 
// Function to find the area of a square
int areaOfSquare(int D)
{
    // Use above formula
    int area = (D * D) / 2;
 
    return area;
}
 
// Driver Code
int main()
{
 
    // Given diagonal of square
    int D = 4;
 
    // Function call
    cout << areaOfSquare(D);
    return 0;
}

Java

// Java program for the above approach
import java.util.*;
 
class GFG{
 
// Function to find the area of a square
static int areaOfSquare(int D)
{
     
    // Use above formula
    int area = (D * D) / 2;
 
    return area;
}
 
// Driver Code
public static void main(String[] args)
{
     
    // Given diagonal of square
    int D = 4;
 
    // Function call
    System.out.print(areaOfSquare(D));
}
}
 
// This code is contributed by PrinciRaj1992

Python3

# Python3 program for the above approach
 
# Function to find the area of a square
def areaOfSquare(D):
 
    # Use above formula
    area = (D * D) // 2;
 
    return area;
 
# Driver Code
if __name__ == '__main__':
 
    # Given diagonal of square
    D = 4;
    # Function call
    print(areaOfSquare(D));
 
# This code is contributed by PrinciRaj1992

C#

// C# program for the above approach
using System;
 
class GFG{
 
// Function to find the area of a square
static int areaOfSquare(int D)
{
     
    // Use above formula
    int area = (D * D) / 2;
 
    return area;
}
 
// Driver Code
public static void Main(String[] args)
{
     
    // Given diagonal of square
    int D = 4;
 
    // Function call
    Console.Write(areaOfSquare(D));
}
}
 
// This code is contributed by amal kumar choubey

Javascript

<script>
    // Javascript program for the above approach
     
    // Function to find the area of a square
    function areaOfSquare(D)
    {
        // Use above formula
           let area = parseInt((D * D) / 2, 10);
 
        return area;
    }
     
    // Given diagonal of square
    let D = 4;
  
    // Function call
    document.write(areaOfSquare(D));
     
</script>

Output:

Time Complexity: O(1)
Auxiliary Space: O(1)

Finding Area of Square using its Perimeter

The Area of the square of given side S is given by:

Area = S * S …(1)

The relation between Side S and Perimeter P is given by:

P =4*S …(2)

Substituting the value of S from Equation (2) in Equation (1), we have:

$Area = (\frac{P}{4})^{2} = \frac{P*P}{4}$

Below is the implementation of the above formula:

C++

// C++ program for the above approach
#include <iostream>
using namespace std;
 
// Function to find the area of a square
int areaOfSquare(int P)
{
    // Use above formula
    int area = (P * P) / 16;
 
    return area;
}
 
// Driver Code
int main()
{
    // Given perimeter of square
    int P = 32;
 
    // Function call
    cout << areaOfSquare(P);
    return 0;
}

Java

// Java program for the above approach
class GFG{
 
// Function to find the area of a square
static int areaOfSquare(int P)
{
     
    // Use above formula
    int area = (P * P) / 16;
 
    return area;
}
 
// Driver Code
public static void main(String[] args)
{
     
    // Given perimeter of square
    int P = 32;
 
    // Function call
    System.out.print(areaOfSquare(P));
}
}
 
// This code is contributed by amal kumar choubey 

Python3

# Python3 program for the above approach
 
# Function to find the area of a square
def areaOfSquare(P):
   
    # Use above formula
    area = (P * P) // 16;
 
    return area;
 
# Driver Code
if __name__ == '__main__':
   
    # Given perimeter of square
    P = 32;
 
    # Function call
    print(areaOfSquare(P));
 
# This code is contributed by gauravrajput1

C#

// C# program for the above approach
using System;
 
class GFG{
 
// Function to find the area of a square
static int areaOfSquare(int P)
{
     
    // Use above formula
    int area = (P * P) / 16;
 
    return area;
}
 
// Driver Code
public static void Main(String[] args)
{
     
    // Given perimeter of square
    int P = 32;
 
    // Function call
    Console.Write(areaOfSquare(P));
}
}
 
// This code is contributed by amal kumar choubey

Javascript

<script>
 
// javascript program for the above approach
// Function to find the area of a square
function areaOfSquare(P)
{
     
    // Use above formula
    var area = (P * P) / 16;
 
    return area;
}
 
// Driver Code
//Given perimeter of square
var P = 32;
 
// Function call
document.write(areaOfSquare(P)); 
 
// This code is contributed by Princi Singh 
</script>

Output:

Time Complexity: O(1)
Auxiliary Space: O(1)

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