Perfect Square String

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Given a String str and the task is to check sum of ASCII value of all characters is a perfect square or not.

Examples :

Input : ddddddddddddddddddddddddd
Output : Yes

Input : GeeksForGeeks
Output : No

Algorithm

Calculate the string length

Calculate sum of ASCII value of all characters

Take the square root of the number sum and store it into variable squareRoot

Take floor value of the squareRoot and subtract from squareRoot

If the difference of floor value of squareRoot and squareRoot is 0 then print “Yes” otherwise “No”

Below is the implementation of the above approach :

C++

// C++ program to find if string is a 
// perfect square or not. 
#include <bits/stdc++.h> 
using namespace std; 
  
bool isPerfectSquareString(string str) 
{ 
    int sum = 0; 
      
    // calculating the length of 
    // the string 
    int len = str.length(); 
      
    // calculating the ASCII value 
    // of the string 
    for (int i = 0; i < len; i++) 
        sum += (int)str[i]; 
      
    // Find floating point value of 
    // square root of x. 
    long double squareRoot = sqrt(sum); 
      
    // If square root is an integer 
    return ((squareRoot -  
             floor(squareRoot)) == 0); 
} 
  
// Driver code 
int main() 
{ 
    string str = "d"; 
      
    if (isPerfectSquareString(str)) 
        cout << "Yes"; 
    else
        cout << "No"; 
} 

Java

// Java program to find if string 
// is a perfect square or not. 
import java.io.*; 
  
class GFG { 
      
    static boolean isPerfectSquareString(String str) 
    { 
        int sum = 0; 
          
        // calculating the length 
        // of the string 
        int len = str.length(); 
          
        // calculating the ASCII  
        // value of the string 
        for (int i = 0; i < len; i++) 
            sum += (int)str.charAt(i); 
          
        // Find floating point value 
        // of square root of x. 
        long squareRoot = (long)Math.sqrt(sum); 
          
        // If square root is an integer 
        return ((squareRoot -  
                Math.floor(squareRoot)) == 0); 
    } 
  
    // Driver code 
    public static void main (String[] args) 
    { 
        String str = "d"; 
      
        if (isPerfectSquareString(str)) 
            System.out.println("Yes"); 
        else
            System.out.println("No"); 
    } 
} 
  
// This code is contributed by Ajit. 

Python3

# Python3 program to find  
# if string is a perfect  
# square or not. 
import math; 
def isPerfectSquareString(str): 
    sum = 0; 
      
    # calculating the length 
    # of the string 
    l = len(str); 
      
    # calculating the ASCII  
    # value of the string 
    for i in range(l): 
        sum = sum + ord(str[i]); 
      
    # Find floating point value 
    # of square root of x. 
    squareRoot = math.sqrt(sum); 
      
    # If square root is an integer 
    return ((squareRoot -
             math.floor(squareRoot)) == 0); 
  
# Driver code 
str = "d"; 
  
if (isPerfectSquareString(str)): 
    print("Yes"); 
else: 
    print("No"); 
  
# This code is contributed by mits 

C#

// C# program to find if string 
// is a perfect square or not. 
using System; 
  
class GFG 
{ 
    static bool isPerfectSquareString(string str) 
    { 
        int sum = 0; 
          
        // calculating the length 
        // of the string 
        int len = str.Length; 
          
        // calculating the ASCII  
        // value of the string 
        for (int i = 0; i < len; i++) 
            sum += (int)str[i]; 
          
        // Find floating point value 
        // of square root of x. 
        double squareRoot = Math.Sqrt(sum); 
        double F = Math.Floor(squareRoot); 
  
        // If square root is an integer 
        return ((squareRoot - F) == 0); 
    } 
  
    // Driver Code 
    public static void Main() 
    { 
        string str = "d"; 
      
        if (isPerfectSquareString(str)) 
            Console.WriteLine("Yes"); 
        else
            Console.WriteLine("No"); 
    } 
} 
  
// This code is contributed by Sam007 

PHP

<?php 
// PHP program to find if string  
// is a perfect square or not. 
  
function isPerfectSquareString($str) 
{ 
    $sum = 0; 
      
    // calculating the length 
    // of the string 
    $len = strlen($str); 
      
    // calculating the ASCII  
    // value of the string 
    for ($i = 0; $i < $len; $i++) 
        $sum += (int)$str[$i]; 
      
    // Find floating point value  
    // of square root of x. 
    $squareRoot = sqrt($sum); 
      
    // If square root is an integer 
    return (($squareRoot -  
            floor($squareRoot)) == 0); 
} 
  
// Driver code 
$str = "d"; 
  
if (isPerfectSquareString($str)) 
    echo "Yes"; 
else
echo "No"; 
  
// This code is contributed by m_kit 
?> 

Javascript

<script> 
  
// JavaScript program to find if string is a 
// perfect square or not. 
  
function isPerfectSquareString(str)  
{ 
    var sum = 0; 
  
    // Calculating the length of 
    // the string 
    var len = str.length; 
  
    // Calculating the ASCII value 
    // of the string 
    for(var i = 0; i < len; i++)  
        sum += str.charCodeAt(i); 
  
    // Find floating point value of 
    // square root of x. 
    var squareRoot = Math.sqrt(sum); 
  
    // If square root is an integer 
    return squareRoot - Math.floor(squareRoot) == 0; 
} 
  
// Driver code 
var str = "d"; 
  
if (isPerfectSquareString(str))  
    document.write("Yes"); 
else 
    document.write("No"); 
      
// This code is contributed by rdtank 
  
</script>

Output

Yes

Time Complexity: O(len), where the len is the length of the string.
Auxiliary Space: O(1)

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