Program to check if a matrix is Binary matrix or not

Given a matrix, the task is to check if that matrix is a Binary Matrix. A Binary Matrix is a matrix in which all the elements are either 0 or 1. It is also called Logical Matrix, Boolean Matrix, Relation Matrix.
Examples:
Input:
{{1, 0, 1, 1},
{0, 1, 0, 1}
{1, 1, 1, 0}}
Output: Yes
Input:
{{1, 0, 1, 1},
{1, 2, 0, 1},
{0, 0, 1, 1}}
Output: No
Approach: Traverse the matrix and check if every element is either 0 or 1. If there is any element other than 0 and 1, print No else print Yes.
Below is the implementation of above approach:
C++
// C++ code to check if a matrix// is binary matrix or not.#include <bits/stdc++.h>using namespace std;#define M 3#define N 4// function to check if a matrix// is binary matrix or notbool isBinaryMatrix(int mat[][N]){ for (int i = 0; i < M; i++) { for (int j = 0; j < N; j++) { // Returns false if element is other than 0 or 1. if (!(mat[i][j] == 0 || mat[i][j] == 1)) return false; } } // Returns true if all the elements // are either 0 or 1. return true;}// Driver codeint main(){ int mat[M][N] = { { 1, 0, 1, 1 }, { 0, 1, 0, 1 }, { 1, 1, 1, 0 } }; if (isBinaryMatrix(mat)) cout << "Yes"; else cout << "No"; return 0;} |
Java
// JAVA code to check if a matrix// is binary matrix or not.import java.io.*;class GFG { static int M = 3; static int N = 4; // function to check if a matrix is binary matrix // or not static boolean isBinaryMatrix(int mat[][]) { for (int i = 0; i < M; i++) { for (int j = 0; j < N; j++) { // Returns false if element is other than 0 or 1. if (!(mat[i][j] == 0 || mat[i][j] == 1)) return false; } } // Returns true if all the elements // are either 0 or 1. return true; } // Driver code public static void main(String args[]) { int mat[][] = { { 1, 0, 1, 1 }, { 0, 1, 0, 1 }, { 1, 1, 1, 0 } }; if (isBinaryMatrix(mat)) System.out.println("Yes"); else System.out.println("No"); }} |
Python3
# Python3 code to check if a matrix# is binary matrix or not.M = 3;N = 4;# function to check if a matrix# is binary matrix or notdef isBinaryMatrix(mat): for i in range(M): for j in range(N): # Returns false if element # is other than 0 or 1. if ((mat[i][j] == 0 or mat[i][j] == 1)==False): return False; # Returns true if all the # elements are either 0 or 1. return True;# Driver codeif __name__=='__main__': mat = [[ 1, 0, 1, 1 ],[0, 1, 0, 1 ],[ 1, 1, 1, 0 ]]; if (isBinaryMatrix(mat)): print("Yes"); else: print("No");# This code is contributed by mits |
C#
// C# code to check if a matrix // is binary matrix or not. using System;class GFG { static int M = 3; static int N = 4; // function to check if a matrix is binary matrix // or not static bool isBinaryMatrix(int [,]mat) { for (int i = 0; i < M; i++) { for (int j = 0; j < N; j++) { // Returns false if element is other than 0 or 1. if (!(mat[i,j] == 0 || mat[i,j] == 1)) return false; } } // Returns true if all the elements // are either 0 or 1. return true; } // Driver code public static void Main() { int [,]mat = { { 1, 0, 1, 1 }, { 0, 1, 0, 1 }, { 1, 1, 1, 0 } }; if (isBinaryMatrix(mat)) Console.WriteLine("Yes"); else Console.WriteLine("No"); } } // This code is contributed by anuj_67. |
PHP
<?php// PHP code to check if a matrix// is binary matrix or not.$M = 3;$N = 4;// function to check if a matrix// is binary matrix or notfunction isBinaryMatrix($mat){ global $M, $N; for ($i = 0; $i < $M; $i++) { for ($j = 0; $j < $N; $j++) { // Returns false if element // is other than 0 or 1. if (!($mat[$i][$j] == 0 || $mat[$i][$j] == 1)) return false; } } // Returns true if all the // elements are either 0 or 1. return true;}// Driver code$mat = array(array( 1, 0, 1, 1 ), array( 0, 1, 0, 1 ), array( 1, 1, 1, 0 ));if (isBinaryMatrix($mat)) echo "Yes";else echo "No";// This code is contributed by mits?> |
Javascript
<script>// JAVA SCRIPT code to check if a matrix// is binary matrix or not. let M = 3; let N = 4; // function to check if a matrix is binary matrix // or not function isBinaryMatrix(mat) { for (let i = 0; i < M; i++) { for (let j = 0; j < N; j++) { // Returns false if element is other than 0 or 1. if (!(mat[i][j] == 0 || mat[i][j] == 1)) return false; } } // Returns true if all the elements // are either 0 or 1. return true; } // Driver code let mat = [[ 1, 0, 1, 1 ], [ 0, 1, 0, 1 ], [ 1, 1, 1, 0 ]]; if (isBinaryMatrix(mat)) document.write("Yes"); else document.write("No"); // this code is contributed by mohan pavan pulamolu</script> |
Output
Yes
Complexity Analysis:
- Time complexity: O( M X N)
- Space Complexity: O(1)
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