Program to find the time remaining for the day to complete

0 1 3 minutes read

Given the current time in the form of HH::MM, where H represents the hours and M, represents the minutes in a 24-hour time format. The task is to calculate the time remaining for the day to complete as HH::MM.
Examples:

Input: HH::MM = 00::01
Output: 23::01

Input: HH::MM = 23::55
Output: 00::05

Approach:

Since the total minutes in a 24 hour complete day is 24 * 60 = 1440 minutes
Calculate the time completed in minutes
Calculate the time remaining in the form of minutes as total minutes – time completed
Convert the time remaining in the form of HH::MM

Below is the implementation of the above approach:

CPP

#include <bits/stdc++.h>
using namespace std;
 
// Function to find the remaining time
void remainingTime(int h, int m)
{
    int totalMin, hoursRemaining, minRemaining;
 
    // Formula for total remaining minutes
    // = 1440 - 60h - m
    totalMin = 1440 - 60 * h - m;
 
    // Remaining hours
    hoursRemaining = totalMin / 60;
 
    // Remaining minutes
    minRemaining = totalMin % 60;
 
    cout << hoursRemaining << "::"
         << minRemaining << endl;
}
 
// Driver code
int main()
{
 
    // Current time
    int h = 0, m = 1;
 
    // Get the remaining time
    remainingTime(h, m);
 
    return 0;
}

Java

class GFG
{
 
// Function to find the remaining time
static void remainingTime(int h, int m)
{
    int totalMin, hoursRemaining, minRemaining;
 
    // Formula for total remaining minutes
    // = 1440 - 60h - m
    totalMin = 1440 - 60 * h - m;
 
    // Remaining hours
    hoursRemaining = totalMin / 60;
 
    // Remaining minutes
    minRemaining = totalMin % 60;
 
    System.out.print(hoursRemaining+ "::"
        + minRemaining +"\n");
}
 
// Driver code
public static void main(String[] args)
{
 
    // Current time
    int h = 0, m = 1;
 
    // Get the remaining time
    remainingTime(h, m);
}
}
 
// This code is contributed by Rajput-Ji

Python

# Function to find the remaining time
def remainingTime(h, m):
 
    # Formula for total remaining minutes
    # = 1440 - 60h - m
    totalMin = 1440 - 60 * h - m
 
    # Remaining hours
    hoursRemaining = totalMin // 60
 
    # Remaining minutes
    minRemaining = totalMin % 60
 
    print(hoursRemaining,"::",minRemaining)
 
# Driver code
 
# Current time
h = 0
m = 1
 
# Get the remaining time
remainingTime(h, m)
 
# This code is contributed by mohit kumar 29

C#

// C# program to Number of pairs of lines
// having integer intersection points
using System;
 
class GFG
{
 
    // Function to find the remaining time
    static void remainingTime(int h, int m)
    {
        int totalMin, hoursRemaining, minRemaining;
     
        // Formula for total remaining minutes
        // = 1440 - 60h - m
        totalMin = 1440 - 60 * h - m;
     
        // Remaining hours
        hoursRemaining = totalMin / 60;
     
        // Remaining minutes
        minRemaining = totalMin % 60;
     
        Console.WriteLine(hoursRemaining+ "::"
                            + minRemaining);
    }
     
    // Driver code
    public static void Main()
    {
     
        // Current time
        int h = 0, m = 1;
     
        // Get the remaining time
        remainingTime(h, m);
    }
}
 
// This code is contributed by AnkitRai01

Javascript

<script>
 
// Javascript program to Number of pairs of lines
// having integer intersection points
 
   
    // Function to find the remaining time
    function remainingTime(h, m)
    {
        var totalMin, hoursRemaining, minRemaining;
       
        // Formula for total remaining minutes
        // = 1440 - 60h - m
         
        totalMin = 1440 - 60 * h - m;
       
        // Remaining hours
         
        hoursRemaining = totalMin / 60;
       
        // Remaining minutes
         
        minRemaining = totalMin % 60;
       
        document.write(Math.trunc(hoursRemaining)+ 
        "::" + minRemaining);
    }
       
    // Driver code
 
       
        // Current time
        var h = 0, m = 1;
       
        // Get the remaining time
        remainingTime(h, m);
         
</script>

Output:

23::59

Time Complexity: O(1)
Auxiliary Space: O(1)

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