XOR of every element of an Array with a given number K

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Given an array arr and a number K, find the new array formed by performing XOR of the corresponding element from the given array with the given number K.
Examples:

Input: arr[] = { 2, 4, 1, 3, 5 }, K = 5
Output: 7 1 4 6 0
Explanation:
2 XOR 5 = 7
4 XOR 5 = 1
1 XOR 5 = 4
3 XOR 5 = 6
5 XOR 5 = 0
Input: arr[] = { 4, 75, 45, 42 }, K = 2
Output: 6 73 47 40

Approach:

Traverse the given array.
Then calculate the XOR of each element with K.
Then store it as the element at that index in the output array.
Print the updated array.

Below is the implementation of the above approach.

CPP

// C++ program to find XOR of every element
// of an array with a given number K
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to construct new array
void constructXORArray(int A[], int n, int K)
{
    int B[n];
 
    // Traverse the array and
    // compute XOR with K
    for (int i = 0; i < n; i++)
        B[i] = A[i] ^ K;
 
    // Print new array
    for (int i = 0; i < n; i++)
        cout << B[i] << " ";
    cout << endl;
}
 
// Driver code
int main()
{
    int A[] = { 2, 4, 1, 3, 5 };
    int K = 5;
    int n = sizeof(A) / sizeof(A[0]);
    constructXORArray(A, n, K);
 
    int B[] = { 4, 75, 45, 42 };
    K = 2;
    n = sizeof(B) / sizeof(B[0]);
    constructXORArray(B, n, K);
 
    return 0;
}

Java

// Java program to find XOR of every element
// of an array with a given number K
import java.util.*;
class GFG
{
 
// Function to construct new array
static void constructXORArray(int A[], int n, int K)
{
      
     int[] B = new int[n];
 
    // Traverse the array and
    // compute XOR with K
    for (int i = 0; i < n; i++)
        B[i] = A[i] ^ K;
 
    // Print new array
    for (int i = 0; i < n; i++)
        System.out.print( B[i] +" ");
    System.out.println();
}
 
// Driver code 
public static void main(String args[]) 
{ 
    int A[] = { 2, 4, 1, 3, 5 };
    int K = 5;
    int n = A.length;
    constructXORArray(A, n, K);
 
    int B[] = { 4, 75, 45, 42 };
    K = 2;
    n = B.length;
    constructXORArray(B, n, K);
 
}
}
 
// This code is contributed by shivanisinghss2110

Python3

# Python program to find XOR of every element
# of an array with a given number K
 
# Function to construct new array
def constructXORArray(A, n, K):
 
    B = [0]*n;
 
    # Traverse the array and
    # compute XOR with K
    for i in range(n):
        B[i] = A[i] ^ K;
 
    # Print new array
    for i in range(n):
        print(B[i], end=" ");
    print();
 
 
# Driver code
if __name__ == '__main__':
    A = [ 2, 4, 1, 3, 5 ];
    K = 5;
    n = len(A);
    constructXORArray(A, n, K);
 
    B = [ 4, 75, 45, 42 ];
    K = 2;
    n = len(B);
    constructXORArray(B, n, K);
# This code contributed by sapnasingh4991

C#

// C# program to find XOR of every element
// of an array with a given number K
using System;
 
class GFG
{
  
// Function to construct new array
static void constructXORArray(int []A, int n, int K)
{
       
     int[] B = new int[n];
  
    // Traverse the array and
    // compute XOR with K
    for (int i = 0; i < n; i++)
        B[i] = A[i] ^ K;
  
    // Print new array
    for (int i = 0; i < n; i++)
        Console.Write( B[i] +" ");
    Console.WriteLine();
}
  
// Driver code 
public static void Main(String []args) 
{ 
    int []A = { 2, 4, 1, 3, 5 };
    int K = 5;
    int n = A.Length;
    constructXORArray(A, n, K);
  
    int []B = { 4, 75, 45, 42 };
    K = 2;
    n = B.Length;
    constructXORArray(B, n, K);
}
}
 
// This code is contributed by Rajput-Ji

Javascript

<script>
    // Javascript program to find XOR of every element 
    // of an array with a given number K 
     
    // Function to construct new array 
    function constructXORArray(A, n, K) 
    { 
        let B = new Array(n); 
 
        // Traverse the array and 
        // compute XOR with K 
        for (let i = 0; i < n; i++) 
            B[i] = A[i] ^ K; 
 
        // Print new array 
        for (let i = 0; i < n; i++) 
            document.write(B[i] + " "); 
        document.write("</br>") 
    } 
     
    let A = [ 2, 4, 1, 3, 5 ]; 
    let K = 5; 
    let n = A.length; 
    constructXORArray(A, n, K); 
   
    let B = [ 4, 75, 45, 42 ]; 
    K = 2; 
    n = B.length; 
    constructXORArray(B, n, K); 
     
    // This code is contributed by divyeshrabadiya07.
</script>

Output:

7 1 4 6 0 
6 73 47 40

Time Complexity: O(n)
Auxiliary Space: O(n)

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