Add two numbers using ++ and/or —

0 0 3 minutes read

Given two numbers, return a sum of them without using operators + and/or -, and using ++ and/or –.
Examples:

Input: x = 10, y = 5
Output: 15

Input: x = 10, y = -5
Output: 10

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The idea is to do y times x++, if y is positive, and do y times x– if y is negative.

C++

// C++ program to add two numbers using ++
#include <bits/stdc++.h>
using namespace std;
 
// Returns value of x+y without using +
int add(int x, int y)
{
    // If y is positive, y times add 1 to x
    while (y > 0 && y--)
        x++;
 
    // If y is negative, y times subtract 1 from x
    while (y < 0 && y++)
        x--;
 
    return x;
}
 
int main()
{
    cout << add(43, 23) << endl;
    cout << add(43, -23) << endl;
    return 0;
}

Java

// java program to add two numbers
// using ++
 
public class GFG {
 
    // Returns value of x+y without
    // using +
    static int add(int x, int y)
    {
 
        // If y is positive, y times
        // add 1 to x
        while (y > 0 && y != 0) {
            x++;
            y--;
        }
 
        // If y is negative, y times
        // subtract 1 from x
        while (y < 0 && y != 0) {
            x--;
            y++;
        }
 
        return x;
    }
 
    // Driver code
    public static void main(String args[])
    {
        System.out.println(add(43, 23));
 
        System.out.println(add(43, -23));
    }
}
 
// This code is contributed by Sam007.

Python3

# python program to add two 
# numbers using ++
 
# Returns value of x + y 
# without using + def add(x, y):
     
    # If y is positive, y 
    # times add 1 to x 
    while (y > 0 and y):
        x = x + 1
        y = y - 1
     
    # If y is negative, y 
    # times subtract 1
    # from x
    while (y < 0 and y) :
        x = x - 1
        y = y + 1
 
    return x
 
# Driver code
print(add(43, 23))
print(add(43, -23))
 
# This code is contributed 
# by Sam007.

C#

// C# program to add two numbers
// using ++
using System;
 
public class GFG {
 
    // Returns value of x+y without
    // using +
    static int add(int x, int y)
    {
 
        // If y is positive, y times
        // add 1 to x
        while (y > 0 && y != 0) {
            x++;
            y--;
        }
 
        // If y is negative, y times
        // subtract 1 from x
        while (y < 0 && y != 0) {
            x--;
            y++;
        }
 
        return x;
    }
 
    // Driver code
    public static void Main()
    {
        Console.WriteLine(add(43, 23));
        Console.WriteLine(add(43, -23));
    }
}
 
// This code is contributed by Sam007.

PHP

<?php
// PHP program to add two
// numbers using ++
 
// Returns value of
// x+y without using +
function add($x, $y) 
{ 
     
    // If y is positive, 
    // y times add 1 to x 
    while ($y > 0 && $y--) 
       $x++;
 
    // If y is negative, 
    // y times subtract
    // 1 from x
    while ($y < 0 && $y++) 
       $x--;
 
    return $x;
}
 
    // Driver Code
    echo add(43, 23), "\n";
    echo add(43, -23), "\n";
 
// This code is contributed by ajit.
?>

Javascript

<script>
 
    // Javascript program to 
    // add two numbers using ++
     
    // Returns value of x+y without
    // using +
    function add(x, y)
    {
   
        // If y is positive, y times
        // add 1 to x
        while (y > 0 && y != 0) {
            x++;
            y--;
        }
   
        // If y is negative, y times
        // subtract 1 from x
        while (y < 0 && y != 0) {
            x--;
            y++;
        }
   
        return x;
    }
     
    document.write(add(43, 23) + "</br>");
      document.write(add(43, -23) + "</br>");
     
</script>

Output:

66
20

Time Complexity: O(y)

Auxiliary Space: O(1)
Thanks to Gaurav Ahirwar for suggesting the above solution.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above

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