Game of Nim with removal of one stone allowed

In Game of Nim, two players take turns removing objects from heaps or the pile of stones.
Suppose two players A and B are playing the game. Each is allowed to take only one stone from the pile. The player who picks the last stone of the pile will win the game. Given N the number of stones in the pile, the task is to find the winner, if player A starts the game.
Examples :
Input : N = 3. Output : Player A
Player A remove stone 1 which is at the top, then Player B remove stone 2 and finally player A removes the last stone. Input : N = 15. Output : Player A
For N = 1, player A will remove the only stone from the pile and wins the game.
For N = 2, player A will remove the first stone and then player B remove the second or the last stone. So player B will win the game.
So, we can observe player A wins when N is odd and player B wins when N is even.
Below is the implementation of this approach:
C++
// C++ program for Game of Nim with removal// of one stone allowed.#include<bits/stdc++.h>using namespace std;// Return true if player A wins, // return false if player B wins.bool findWinner(int N){ // Checking the last bit of N. return N&1;}// Driven Programint main(){ int N = 15; findWinner(N)? (cout << "Player A";): (cout << "Player B";); return 0;} |
Java
// JAVA Code For Game of Nim with// removal of one stone allowedimport java.util.*;class GFG { // Return true if player A wins, // return false if player B wins. static int findWinner(int N) { // Checking the last bit of N. return N & 1; } /* Driver program to test above function */ public static void main(String[] args) { int N = 15; if(findWinner(N)==1) System.out.println("Player A"); else System.out.println("Player B"); }}// This code is contributed by Arnav Kr. Mandal. |
Python3
# Python3 code for Game of Nim with# removal of one stone allowed.# Return true if player A wins, # return false if player B wins.def findWinner( N ): # Checking the last bit of N. return N & 1 # Driven ProgramN = 15print("Player A" if findWinner(N) else "Player B") # This code is contributed by "Sharad_Bhardwaj". |
C#
// C# Code For Game of Nim with// removal of one stone allowedusing System;class GFG { // Return true if player A wins, // return false if player B wins. static int findWinner(int N) { // Checking the last bit of N. return N & 1; } /* Driver program to test above function */ public static void Main() { int N = 15; if(findWinner(N) == 1) Console.Write("Player A"); else Console.Write("Player B"); }}// This code is contributed by vt_m. |
PHP
<?php// PHP program for Game of // Nim with removal of one// stone allowed.// Return true if player A wins, // return false if player B wins.function findWinner($N){ // Checking the last bit of N.return $N&1;}// Driver Code$N = 15;if(findWinner($N))echo "Player A"; elseecho "Player B";// This code is contributed by vt_m.?> |
Javascript
<script>// JavaScript program For Game of Nim with// removal of one stone allowed // Return true if player A wins, // return false if player B wins. function findWinner(N) { // Checking the last bit of N. return N & 1; }// Driver code let N = 15; if(findWinner(N)==1) document.write("Player A"); else document.write("Player B"); // This code is contributed by sanjoy_2.</script> |
Output :
Player A
Time Complexity: O(1).
Auxiliary Space: O(1)
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