C++ Program to Find maximum element of each row in a matrix

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Given a matrix, the task is to find the maximum element of each row.

Examples:

Input :  [1, 2, 3]
         [1, 4, 9]
         [76, 34, 21]

Output :
3
9
76

Input : [1, 2, 3, 21]
        [12, 1, 65, 9]
        [1, 56, 34, 2]
Output :
21
65
56

Approach : The approach is very simple. The idea is to run the loop for no_of_rows. Check each element inside the row and find for the maximum element. Finally, print the element.

Below is the implementation :

C++14

// C++ program to find maximum
// element of each row in a matrix
#include <bits/stdc++.h>
using namespace std;
const int N = 4;
 
// Print array element
void printArray(vector<int>& result, int no_of_rows)
{
    for (int i = 0; i < no_of_rows; i++) {
        cout << result[i] << " ";
    }
}
 
// Function to get max element
void maxelement(int no_of_rows, vector<vector<int> >& arr)
{
    int i = 0;
 
    // Initialize max to 0 at beginning
    // of finding max element of each row
    int max = 0;
    vector<int> result(no_of_rows);
    while (i < no_of_rows) {
        for (int j = 0; j < N; j++) {
            if (arr[i][j] > max) {
                max = arr[i][j];
            }
        }
        result[i] = max;
        max = 0;
        i++;
    }
    printArray(result, no_of_rows);
}
 
// Driver code
int main()
{
    vector<vector<int> > arr = { { 3, 4, 1, 8 },
                                 { 1, 4, 9, 11 },
                                 { 76, 34, 21, 1 },
                                 { 2, 1, 4, 5 } };
    // Calling the function
    maxelement(4, arr);
    return 0;
}
 
// This code is contributed by Rajput-Ji

Output

8 11 76 5

Time Complexity: O(M*N), where M and N are no of rows and column of given matrix
Auxiliary Space: O(M)

Please refer complete article on Find maximum element of each row in a matrix for more details!

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