Python – Restrict Tuples by frequency of first element’s value

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Given a Tuple list, the task is to write a Python program to restrict the frequency of the 1st element of tuple values to at most K.

Examples:

Input : test_list = [(2, 3), (3, 3), (1, 4), (2, 4), (2, 5), (3, 4), (1, 4), (3, 4), (4, 7)], K = 2

Output : [(2, 3), (3, 3), (1, 4), (2, 4), (3, 4), (1, 4), (4, 7)]

Explanation : 2 occurs 2 times in result list, (2, 5), the 3rd occurrence is omitted.

Input : test_list = [(2, 3), (3, 3), (1, 4), (2, 4), (2, 5), (3, 4), (1, 4), (3, 4), (4, 7)], K = 3

Output : [(2, 3), (3, 3), (1, 4), (4, 7)]

Explanation : 2, 3, 1, 4 restricted to their 1st occurrence.

Method 1 : Using loop + keys() + conditional statements

In this, we perform task of memorizing count of each element of 1st position of tuples, and omit if its occurrences increases K.

Python3

# Python3 code to demonstrate working of
# Restrict Tuples by frequency of first element's value
# Using loop + keys() + conditional statements
 
# initializing list
test_list = [(2, 3), (3, 3), (1, 4), (2, 4), (2, 5),
             (3, 4), (1, 4), (3, 4), (4, 7)]
 
# printing original list
print("The original list is : " + str(test_list))
 
# initializing K
K = 2
 
res = []
mem = dict()
for sub in test_list:
 
    # check in memory
    if sub[0] not in mem.keys():
        mem[sub[0]] = 1
    else:
        mem[sub[0]] += 1
 
    # add if less than K frequency
    if mem[sub[0]] <= K:
        res.append(sub)
 
# printing result
print("Filtered tuples : " + str(res))

Output:

The original list is : [(2, 3), (3, 3), (1, 4), (2, 4), (2, 5), (3, 4), (1, 4), (3, 4), (4, 7)]
Filtered tuples : [(2, 3), (3, 3), (1, 4), (2, 4), (3, 4), (1, 4), (4, 7)]

Time Complexity: O(n)
Auxiliary Space: O(n)

Method #2 : Using defaultdict() + filter() + lambda

In this, we perform task of memorizing using defaultdict() and filter() and lambda functions are used for the task of checking and adding to result upon meeting of condition.

Python3

# Python3 code to demonstrate working of
# Restrict Tuples by frequency of first element's value
# Using defaultdict() + filter() + lambda
from collections import defaultdict
 
# initializing list
test_list = [(2, 3), (3, 3), (1, 4), (2, 4), (2, 5),
             (3, 4), (1, 4), (3, 4), (4, 7)]
 
# printing original list
print("The original list is : " + str(test_list))
 
# initializing K
K = 2
 
mem = defaultdict(list)
 
# filtering result using filter() and lambda function
res = list(filter(lambda sub: mem[sub[0]].append(
    sub[0]) or len(mem[sub[0]]) <= K, test_list))
 
# printing result
print("Filtered tuples : " + str(res))

Output:

The original list is : [(2, 3), (3, 3), (1, 4), (2, 4), (2, 5), (3, 4), (1, 4), (3, 4), (4, 7)]
Filtered tuples : [(2, 3), (3, 3), (1, 4), (2, 4), (3, 4), (1, 4), (4, 7)]

Time Complexity: O(n) where n is the number of elements in the list “test_list”. The defaultdict() + filter() + lambda is used to perform the task and it takes O(n) time.
Auxiliary Space: O(n), new list of size O(n) is created where n is the number of elements in the list