Python | Pandas TimedeltaIndex.difference

0 0 1 minute read

Python is a great language for doing data analysis, primarily because of the fantastic ecosystem of data-centric python packages. Pandas is one of those packages and makes importing and analyzing data much easier.
Pandas TimedeltaIndex.difference() function return a new Index with elements from the index that are not in other. This is the set difference of two Index objects. It’s sorted if sorting is possible.

Syntax : TimedeltaIndex.difference(other)
Parameters :
other : Index or array-like
Return : difference : Index

Example #1: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.

Python3

# importing pandas as pd
import pandas as pd
 
# Create the first TimedeltaIndex object
tidx1 = pd.TimedeltaIndex(data =['06:05:01.000030', '+23:59:59.999999', 
                                 '22 day 2 min 3us 10ns', '+23:29:59.999999', 
                                                         '+12:19:59.999999'])
 
# Create the second TimedeltaIndex object
tidx2 = pd.TimedeltaIndex(data =['09:11:18.000030', '+23:59:59.999999',
                                 '9 day 18 min 3us ', '+23:29:59.999999',
                                                     '+12:19:59.999999'])
 
# Print the first and second TimedeltaIndex object
print(tidx1, "\n", tidx2)

Output :

Now we will use the TimedeltaIndex.difference() function to find the set difference.

Python3

# find the set difference
tidx1.difference(tidx2)

Output :

As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.

Example #2: Use TimedeltaIndex.difference() function to find the set difference of two TimedeltaIndex objects.

Python3

# importing pandas as pd
import pandas as pd
 
# Create the first TimedeltaIndex object
tidx1 = pd.TimedeltaIndex(start ='1 days 02:00:12.001124', periods = 5,
                                              freq ='D', name ='Koala')
 
# Create the second TimedeltaIndex object
tidx2 = pd.TimedeltaIndex(start ='3 days 02:00:12.001124', periods = 5,
                                              freq ='D', name ='Koala')
 
# Print the first and second TimedeltaIndex object
print(tidx1, "\n", tidx2)

Output :

Now we will use the TimedeltaIndex.difference() function to find the set difference.

Python3

# find the set difference
tidx1.difference(tidx2)

Output :

As we can see in the output, the TimedeltaIndex.difference() function has returned a new object which contains only those elements which are unique to tidx1.