Integer sum() Method in Java

The java.lang.Integer.sum() is a built-in method in java that returns the sum of its arguments. The method adds two integers together as per the + operator.
Syntax :
public static int sum(int a, int b)
Parameter: The method accepts two parameters that are to be added with each other: a : the first integer value. b : the second integer value.
Return Value: The method returns the sum of its arguments.
Exception: The method throws an ArithmeticException when the result overflows an int.
Examples:
Input: a = 170, b = 455 Output: 625 Input: a = 45, b = 45 Output: 90
Below programs illustrate the Java.lang.Integer.sum() method:
Program 1: For a positive number.
java
// Java program to illustrate the// Java.lang.Integer.sum() methodimport java.lang.*;public class Geeks { public static void main(String[] args) { int a = 62; int b = 18; // It will return the sum of two arguments. System.out.println("The sum is =" + Integer.sum(a, b)); }} |
Output:
The sum is =80
Program 2: Below program illustrates the exception.
java
// Java program to illustrate the// Java.lang.Integer.sum() methodimport java.lang.*;public class Geeks { public static void main(String[] args) { // When very large integer is taken int a = 92374612162; int b = 181; // It will return the sum of two arguments. System.out.println("The sum is =" + Integer.sum(a, b)); }} |
Output:
prog.java:8: error: integer number too large: 92374612162
int a = 92374612162;
^
1 error
Program 3 : Find the sum of integers using a loop
Java
import java.io.*;public class Arrays { public static void main(String[] args) { int[] arr = { 2, 4, 6, 8, 10 }; int sum = 0; for (int i = 0; i < arr.length; i++) { sum += arr[i]; } System.out.println("Sum of array elements is: " + sum); }} |
Output
Sum of array elements is: 30



