Java Program to Find the Largest of three Numbers

Problem Statement: Given three numbers x, y, and z of which aim is to get the largest among these three numbers.
Example:
Input: x = 7, y = 20, z = 56 Output: 56 // value stored in variable z
Flowchart For Largest of 3 numbers:
Algorithm to find the largest of three numbers:
1. Start
2. Read the three numbers to be compared, as A, B and C
3. Check if A is greater than B.
  3.1 If true, then check if A is greater than C
         If true, print 'A' as the greatest number
          If false, print 'C' as the greatest number
  3.2 If false, then check if B is greater than C
        If true, print 'B' as the greatest number
        If false, print 'C' as the greatest number
4. End
Approaches:
- Using Ternary operator
 - Using if-else
 
Approach 1: Using Ternary operator
The syntax for the conditional operator:
ans = (conditional expression) ? execute if true : execute if false
- If the condition is true then execute the statement before the colon
 - If the condition is false then execute a statement after colon so
 
largest = z > (x>y ? x:y) ? z:((x>y) ? x:y);
Illustration:
x = 5, y= 10, z = 3 largest = 3>(5>10 ? 5:10) ? 3: ((5>10) ? 5:10); largest = 3>10 ? 3 : 10 largest = 10
Java
// Java Program to Find the Biggest of 3 Numbers// Importing generic Classes/Filesimport java.io.*;class GFG {       // Function to find the biggest of three numbers    static int biggestOfThree(int x, int y, int z)    {        return z > (x > y ? x : y) ? z : ((x > y) ? x : y);    }    // Main driver function    public static void main(String[] args)    {        // Declaring variables for 3 numbers        int a, b, c;        // Variable holding the largest number        int largest;        a = 5;        b = 10;        c = 3;        // Calling the above function in main        largest = biggestOfThree(a, b, c);        // Printing the largest number        System.out.println(largest                           + " is the largest number.");    }} | 
Output
10 is the largest number.
Approach 2: Using the if-else statements
In this method, if-else statements will compare and check for the largest number by comparing numbers. ‘If’ will check whether ‘x’ is greater than ‘y’ and ‘z’ or not. ‘else if’ will check whether ‘y’ is greater than ‘x’ and ‘z’ or not. And if both the conditions are false then ‘z’ will be the largest number.
Java
// Java Program to Find the Biggest of 3 Numbers// Importing generic Classes/Filesimport java.io.*;class GFG {    // Function to find the biggest of three numbers    static int biggestOfThree(int x, int y, int z)    {        // Comparing all 3 numbers        if (x >= y && x >= z)            // Returning 1st number if largest            return x;        // Comparing 2nd no with 1st and 3rd no        else if (y >= x && y >= z)            // Return z if the above conditions are false            return y;        else            // Returning 3rd no, Its sure it is greatest            return z;    }    // Main driver function    public static void main(String[] args)    {        int a, b, c, largest;        // Considering random integers three numbers        a = 5;        b = 10;        c = 3;        // Calling the function in main() body        largest = biggestOfThree(a, b, c);        // Printing the largest number        System.out.println(largest                           + " is the largest number.");    }} | 
 
 
Output
10 is the largest number.
Approach 3 : Using Collections.max() method and ArrayList
Java
// Java Program to Find the Largest of three Numbers// Using Collections.max() methodimport java.lang.*;import java.util.*;class GFG {    public static void main(String[] args)    {        int a, b, c;        // Considering random integers three numbers        a = 5;        b = 10;        c = 3;        ArrayList<Integer> x = new ArrayList<>();        x.add(a);        x.add(b);        x.add(c);        // Printing the largest number        System.out.println(Collections.max(x)                           + " is the largest number.");    }} | 
Output
10 is the largest number.
Time Complexity: O(n)
Auxiliary Space: O(n), where n is length of ArrayList.
				
					



