Generate Infinite Stream of Integers in Java

Given the task is to generate an infinite sequential unordered stream of integers in Java.
This can be done in following ways:
- Using IntStream.iterate():
- Using the IntStream.iterate() method, iterate the IntStream with i by incrementing the value with 1.
- Print the IntStream with the help of forEach() method.
importjava.util.stream.*;publicclassGFG {// Main methodpublicstaticvoidmain(String[] args){IntStream// Iterate the IntStream with i// by incrementing the value with 1.iterate(0, i -> i +1)// Print the IntStream// using forEach() method..forEach(System.out::println);}}Output:
0 1 2 3 4 5 . . .
- Using Random.ints():
- Get the next integer using ints() method
- Print the IntStream with the help of forEach() method.
importjava.util.stream.*;importjava.util.*;publicclassGFG {// Main methodpublicstaticvoidmain(String[] args){// Create a Random objectRandom random =newRandom();random// Get the next integer// using ints() method.ints()// Print the IntStream// using forEach() method..forEach(System.out::println);}}Output:
-1214876682 911266110 1224044471 -1867062635 1893822159 1226183018 741533414 . . .
- Using IntStream.generate():
- Generate the next integer using IntStream.generate() and Random.nextInt()
- Print the IntStream with the help of forEach() method.
importjava.util.stream.*;importjava.util.*;publicclassGFG {// Main methodpublicstaticvoidmain(String[] args){// Create a Random objectRandom random =newRandom();IntStream// Generate the next integer// using IntStream.generate()// and Random.nextInt().generate(random::nextInt)// Print the IntStream// using forEach() method..forEach(System.out::println);}}Output:
-798555363 -531857014 1861939261 273120213 -739170342 1295941815 870955405 -631166457 . . .



