numpy.isfortran() in Python
numpy.isfortran(array) : This is a logical function that checks whether array is Fortran contiguous or not.
Order : [C-contiguous, F-contiguous, A-contiguous; optional]
C-contiguous order in memory(last index varies the fastest). C order means that operating row-rise on the array will be slightly quicker.
FORTRAN-contiguous order in memory (first index varies the fastest). F order means that column-wise operations will be faster.
‘A’ means to read / write the elements in Fortran-like index order if, array is Fortran contiguous in memory, C-like order otherwise.
Parameters :
array : [array_like]Input array
Return :
True, if array is Fortran; else False
Code 1 :
# Python program explaining # isfortran() function import numpy as np in_array = np.array([[1, 2, 3], [4, 5, 6]], order='C') print ("Input array : \n", in_array) exp2_values = np.exp2(in_array) print ("\nisfortran : ", np.isfortran(in_array)) |
Output :
Input array : [[1 2 3] [4 5 6]] isfortran : False
Code 2 :
# Python program explaining # isfortran() function import numpy as np in_array = np.array([[1, 2, 3], [4, 5, 6]], order='F') print ("Input array : \n", in_array) exp2_values = np.exp2(in_array) print ("\nisfortran : ", np.isfortran(in_array)) |
Output :
Input array : [[1 2 3] [4 5 6]] isfortran : True
References :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.isfortran.html#numpy.isfortran
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