Java Program to Modify given array to a non-decreasing array by rotation

Given an array arr[] of size N (consisting of duplicates), the task is to check if the given array can be converted to a non-decreasing array by rotating it. If it’s not possible to do so, then print “No“. Otherwise, print “Yes“.
Examples:
Input: arr[] = {3, 4, 5, 1, 2}
Output: Yes
Explanation:Â After 2 right rotations, the array arr[] modifies to {1, 2, 3, 4, 5}Input: arr[] = {1, 2, 4, 3}
Output: No
Approach: The idea is based on the fact that a maximum of N distinct arrays can be obtained by rotating the given array and check for each individual rotated array, whether it is non-decreasing or not. Follow the steps below to solve the problem:
- Initialize a vector, say v, and copy all the elements of the original array into it.
- Sort the vector v.
- Traverse the original array and perform the following steps:
- Rotate by 1 in each iteration.
- If the array becomes equal to vector v, print “Yes“. Otherwise, print “No“.
Below is the implementation of the above approach:
Java
// Java program for the above approachimport java.util.*;  class GFG{    // Function to check if a  // non-decreasing array can be obtained  // by rotating the original array  static void rotateArray(int[] arr, int N)  {    // Stores copy of original array    int[] v = arr;      // Sort the given vector    Arrays.sort(v);      // Traverse the array    for (int i = 1; i <= N; ++i) {        // Rotate the array by 1      int x = arr[N - 1];      i = N - 1;      while(i > 0){        arr[i] = arr[i - 1];        arr[0] = x;        i -= 1;      }        // If array is sorted      if (arr == v) {          System.out.print("YES");        return;      }    }      // If it is not possible to    // sort the array    System.out.print("NO");  }    // Driver Code  public static void main(String[] args)  {      // Given array    int[] arr = { 3, 4, 5, 1, 2 };      // Size of the array    int N = arr.length;      // Function call to check if it is possible    // to make array non-decreasing by rotating    rotateArray(arr, N);  }}  // This code is contributed by splevel62. |
YES
Time Complexity: O(N2)
Auxiliary Space: O(N)
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