Program to print Reverse Floyd’s triangle

Floyd’s triangle is a triangle with first natural numbers. Task is to print reverse of Floyd’s triangle.
Examples:
Input : 4 Output : 10 9 8 7 6 5 4 3 2 1 Input : 5 Output : 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1
C++
// CPP program to print reverse of // floyd's triangle #include <bits/stdc++.h> using namespace std; void printReverseFloyd(int n) { int curr_val = n * (n + 1) / 2; for (int i = n; i >= 1; i--) { for (int j = i; j >= 1; j--) { cout << setprecision(2); cout << curr_val-- << " "; } cout << endl; } } // Driver's Code int main() { int n = 7; printReverseFloyd(n); return 0; } // this article is contributed by manish kumar rai |
Java
// Java program to print reverse of // floyd's triangle import java.io.*; class GFG { static void printReverseFloyd(int n) { int curr_val = n * (n + 1) / 2; for (int i = n; i >= 1; i--) { for (int j = i; j >= 1; j--) { System.out.printf("%2d ", curr_val--); } System.out.println(""); } } // Driver method public static void main(String[] args) { int n = 7; printReverseFloyd(n); } } // this article is contributed by manish kumar rai |
Python3
# Python3 program to print reverse of # floyd's triangle def printReverseFloyd(n): curr_val = int(n*(n + 1)/2) for i in range(n + 1, 1, -1): for j in range(i, 1, -1): print(curr_val, end =" ") curr_val -= 1 print("") # Driver code n = 7printReverseFloyd(n) |
C#
// C# program to print reverse // of floyd's triangle using System; using System.Globalization; class GFG { static void printReverseFloyd(int n) { int curr_val = n * (n + 1) / 2; for (int i = n; i >= 1; i--) { for (int j = i; j >= 1; j--) { Console.Write(curr_val-- + " "); } Console.WriteLine(""); } } // Driver Code public static void Main() { int n = 7; printReverseFloyd(n); } } // This code is contributed by Sam007 |
PHP
<?php // PHP program to print reverse // of floyd's triangle function printReverseFloyd($n) { $curr_val = $n * ($n + 1) / 2; for ($i = $n; $i >= 1; $i--) { for ( $j = $i; $j >= 1; $j--) { echo $curr_val-- , " "; } echo " \n"; } } // Driver Code $n = 7; printReverseFloyd($n); // This code is contributed by ajit ?> |
Javascript
<script> // Javascript program to print reverse of // floyd's triangle function printReverseFloyd(n) { let curr_val = n * (n + 1) / 2; for (let i = n; i >= 1; i--) { for (let j = i; j >= 1; j--) { document.write(curr_val-- + " "); } document.write("<br/>"); } } // Driver Code let n = 7; printReverseFloyd(n); </script> |
Output:
28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1
Time complexity: O(n2) for given input n
Auxiliary space: O(1)
Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 zambiatek!
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 zambiatek!



