Program to find volume and surface area of pentagonal prism

0 0 3 minutes read

A prism that has 5 rectangular faces and 2 parallel pentagonal bases is a pentagonal prism. So you are given the apothem length(a), base length(b) and height(h) of the pentagonal prism. you have to find the surface area and the volume of the Pentagonal Prism.
Examples:

Input : a=3, b=5, h=6
Output :surface area=225, volume=225

Input : a=2, b=3, h=5
Output :surface area=105, volume=75

In this figure,
a– apothem length of the Pentagonal Prism.
b– base length of the Pentagonal Prism.
h– height of the Pentagonal Prism.
Formulas:Below are the formulas for calculating the surface area and the volume of the Pentagonal Prism.

$surface\ Area(A)= 5\times a\times b + 5\times b\times h$

$Volume(v)= \frac{5}{2}\times b\times h$

C++

// CPP program to find
// surface area and volume of the
// Pentagonal Prism
#include <bits/stdc++.h>
using namespace std;
 
// function for surface area
float surfaceArea(float a, float b, float h)
{
    return 5 * a * b + 5 * b * h;
}
 
// function for VOlume
float volume(float b, float h)
{
    return (5 * b * h) / 2;
}
 
// Driver function
int main()
{
    float a = 5;
    float b = 3;
    float h = 7;
 
    cout << "surface area= " << surfaceArea(a, b, h) << ", ";
 
    cout << "volume= " << volume(b, h);
}

Java

// Java program to find
// surface area and volume of the
// Pentagonal Prism
import java.util.*;
 
class solution
{
 
// function for surface area
static float surfaceArea(float a, float b, float h)
{
 
    return 5 * a * b + 5 * b * h;
 
}
 
// function for VOlume
static float volume(float b, float h)
{
 
    return (5 * b * h) / 2;
 
}
 
// Driver function
public static void main(String arr[])
{
    float a = 5;
    float b = 3;
    float h = 7;
 
    System.out.println( "surface area= "+surfaceArea(a, b, h)+", ");
 
    System.out.println("volume= "+volume(b, h));
}
}

Python3

# Python 3 program to find surface area
# and volume of the Pentagonal Prism
 
# function for surface area
def surfaceArea(a, b, h):
    return 5 * a * b + 5 * b * h
 
# function for VOlume
def volume(b, h):
    return (5 * b * h) / 2
 
# Driver Code
if __name__ == '__main__':
    a = 5
    b = 3
    h = 7
 
    print("surface area =", surfaceArea(a, b, h),
                   ",", "volume =", volume(b, h))
 
# This code is contributed by
# Sanjit_Prasad

C#

// C# program to find surface
// area and volume of the
// Pentagonal Prism
using System;
 
class GFG
{
 
// function for surface area
static float surfaceArea(float a, 
                         float b, float h)
{
    return 5 * a * b + 5 * b * h;
}
 
// function for VOlume
static float volume(float b, float h)
{
    return (5 * b * h) / 2;
}
 
// Driver Code
public static void Main()
{
    float a = 5;
    float b = 3;
    float h = 7;
 
    Console.WriteLine("surface area = " + 
            surfaceArea(a, b, h) + ", ");
 
    Console.WriteLine("volume = " +
                     volume(b, h));
}
}
 
// This code is contributed by vt_m

PHP

<?php
// PHP program to find
// surface area and volume 
// of the Pentagonal Prism
 
// function for surface area
function surfaceArea($a, $b, $h)
{
    return 5 * $a * $b + 
           5 * $b * $h;
}
 
// function for VOlume
function volume($b, $h)
{
    return (5 * $b * $h) / 2;
}
 
// Driver Code
$a = 5;
$b = 3;
$h = 7;
 
echo "surface area = " , 
      surfaceArea($a, $b, $h) , ", ";
 
echo "volume = " , volume($b, $h);
 
// This code is contributed by vt_m
?>

Javascript

<script>
// javascript program to find
// surface area and volume of the
// Pentagonal Prism
 
// function for surface area
function surfaceArea( a,  b,  h)
{
    return 5 * a * b + 5 * b * h;
}
 
// function for VOlume
function volume( b,  h)
{
    return (5 * b * h) / 2;
}
 
// Driver function
    let a = 5;
    let b = 3;
    let h = 7;
 
    document.write( "surface area= " + surfaceArea(a, b, h) + ", ");
 
    document.write( "volume= " + volume(b, h));
     
// This code is contributed by todaysgaurav 
 
</script>

Output:

surface area= 180, volume= 52.5

Time complexity: O(1)

Auxiliary Space: O(1)

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