Check if the tower of sight issue occurs or not
Given four co-ordinates A, B, C and D where towers need to be constructed, the task is to check if the tower of sight issue occurs or not.
Tower of sight issue occurs if the towers at A or C lies in the line joining B and D or vice versa.
Examples:
Input: A = (0, 0), B = (0, -2), C = (2, 0), D = (0, 2)
Output: Yes
Explanation:
Tower A lies in the line joining B and D.
Input: A = (0, 0), B = (0, -2), C = (2, 0), D = (0, -5)
Output: No
Explanation:
No intersection occurs.
Approach:
- If A and C are parallel to the X-axis, check if B or D has y coordinate equal to that of A and C and x coordinate in between that of A and C.
- If A and C are parallel to the Y-axis, check if B or D has x coordinate equal to that of A and C and y coordinate in between that of A and C.
- Otherwise, check if B or D satisfies the line equation of A and C.
- Similarly follow the above three steps to check if A or C lies in between B or D.
Below code is the implementation of the above approach:
C++
// C++ program to check if tower// of sight issue occurs or not#include <bits/stdc++.h>using namespace std;// Function to check if point p lies in// between the line joining p1 and p2int checkIntersection(pair<int, int> p1, pair<int, int> p2, pair<int, int> p){ int val; // If parallel to X-axis if (p1.second == p2.second && p1.second == p.second) { if (p.first <= max(p1.first, p2.first) && (p.first >= min(p1.first, p2.first))) // Point p lies between p1 and p2 return 1; } // If parallel to Y-axis if (p1.first == p2.first && p1.first == p.first) { if (p.second <= max(p1.second, p2.second) && (p.second >= min(p1.second, p2.second))) // Point p lies between p1 and p2 return 1; } // If point p satisfies the equation // of line joining p1 and p2 else { val = (p.second - p1.second) * (p2.first - p1.first) - (p.first - p1.first) * (p2.second - p1.second); if (val == 0) if ((p.first <= max(p1.first, p2.first) && (p.first >= min(p1.first, p2.first))) && (p.second <= max(p1.second, p2.second) && (p.second >= min(p1.second, p2.second)))) return 1; } return 0;}// Function to check if tower// of sight issue occurredvoid towerOfSight(pair<int, int> a, pair<int, int> b, pair<int, int> c, pair<int, int> d){ int flag = 0; if (checkIntersection(a, c, b)) // B lies between AC flag = 1; else if (checkIntersection(a, c, d)) // D lies between AC flag = 1; else if (checkIntersection(b, d, a)) // A lies between BD flag = 1; else if (checkIntersection(b, d, c)) // C lies between BD flag = 1; flag ? cout << "Yes\n" : cout << "No\n";}// Driver codeint main(){ // Point A pair<int, int> a = { 0, 0 }; // Point B pair<int, int> b = { 0, -2 }; // Point C pair<int, int> c = { 2, 0 }; // Point D pair<int, int> d = { 0, 2 }; towerOfSight(a, b, c, d); return 0;} |
Java
// Java program to check if tower// of sight issue occurs or notclass GFG{static class pair{ int first, second; public pair(int first, int second) { this.first = first; this.second = second; } } // Function to check if point p lies in// between the line joining p1 and p2static int checkIntersection(pair p1, pair p2, pair p){ int val; // If parallel to X-axis if (p1.second == p2.second && p1.second == p.second) { if (p.first <= Math.max(p1.first, p2.first) && (p.first >= Math.min(p1.first, p2.first))) // Point p lies between p1 and p2 return 1; } // If parallel to Y-axis if (p1.first == p2.first && p1.first == p.first) { if (p.second <= Math.max(p1.second, p2.second) && (p.second >= Math.min(p1.second, p2.second))) // Point p lies between p1 and p2 return 1; } // If point p satisfies the equation // of line joining p1 and p2 else { val = (p.second - p1.second) * (p2.first - p1.first) - (p.first - p1.first) * (p2.second - p1.second); if (val == 0) if ((p.first <= Math.max(p1.first, p2.first) && (p.first >= Math.min(p1.first, p2.first))) && (p.second <= Math.max(p1.second, p2.second) && (p.second >= Math.min(p1.second, p2.second)))) return 1; } return 0;} // Function to check if tower// of sight issue occurredstatic void towerOfSight(pair a, pair b, pair c, pair d){ int flag = 0; if (checkIntersection(a, c, b) == 1) // B lies between AC flag = 1; else if (checkIntersection(a, c, d) == 1) // D lies between AC flag = 1; else if (checkIntersection(b, d, a) == 1) // A lies between BD flag = 1; else if (checkIntersection(b, d, c) == 1) // C lies between BD flag = 1; System.out.print(flag==1?"Yes\n":"No\n");} // Driver codepublic static void main(String[] args){ // Point A pair a = new pair( 0, 0 ); // Point B pair b = new pair( 0, -2 ); // Point C pair c = new pair( 2, 0 ); // Point D pair d = new pair( 0, 2 ); towerOfSight(a, b, c, d); }}// This code is contributed by Rajput-Ji |
Python3
# Python 3 program to check if tower# of sight issue occurs or not # Function to check if point p lies in# between the line joining p1 and p2def checkIntersection(p1,p2,p): # If parallel to X-axis if (p1[1] == p2[1] and p1[1] == p[1]): if (p[0] <= max(p1[0], p2[0]) and (p[0] >= min(p1[0], p2[0]))): # Point p lies between p1 and p2 return 1 # If parallel to Y-axis if (p1[0] == p2[0] and p1[0] == p[0]): if (p[1] <= max(p1[1], p2[1]) and (p[1] >= min(p1[1], p2[1]))): # Point p lies between p1 and p2 return 1 # If point p satisfies the equation # of line joining p1 and p2 else : val = ((p[1] - p1[1])*(p2[0] - p1[0]) - (p[0] - p1[0]) * (p2[1] - p1[1])) if (val == 0): if ((p[0] <= max(p1[0], p2[0]) and (p[0] >= min(p1[0], p2[0]))) and (p[1] <= max(p1[1], p2[1]) and (p[1] >= min(p1[1], p2[1])))): return 1 return 0 # Function to check if tower# of sight issue occurreddef towerOfSight(a, b, c, d): flag = 0 if (checkIntersection(a, c, b)): # B lies between AC flag = 1 elif (checkIntersection(a, c, d)): # D lies between AC flag = 1 elif (checkIntersection(b, d, a)): # A lies between BD flag = 1 elif (checkIntersection(b, d, c)): # C lies between BD flag = 1 if(flag): print("Yes") else: print("No") # Driver codeif __name__ == "__main__": # Point A a = [ 0, 0 ] # Point B b = [ 0, -2 ] # Point C c = [ 2, 0 ] # Point D d = [ 0, 2 ] towerOfSight(a, b, c, d) # This code is contributed by chitranayal |
C#
// C# program to check if tower// of sight issue occurs or notusing System;class GFG{ class pair{ public int first, second; public pair(int first, int second) { this.first = first; this.second = second; } } // Function to check if point p lies in// between the line joining p1 and p2static int checkIntersection(pair p1, pair p2, pair p){ int val; // If parallel to X-axis if (p1.second == p2.second && p1.second == p.second) { if (p.first <= Math.Max(p1.first, p2.first) && (p.first >= Math.Min(p1.first, p2.first))) // Point p lies between p1 and p2 return 1; } // If parallel to Y-axis if (p1.first == p2.first && p1.first == p.first) { if (p.second <= Math.Max(p1.second, p2.second) && (p.second >= Math.Min(p1.second, p2.second))) // Point p lies between p1 and p2 return 1; } // If point p satisfies the equation // of line joining p1 and p2 else { val = (p.second - p1.second) * (p2.first - p1.first) - (p.first - p1.first) * (p2.second - p1.second); if (val == 0) if ((p.first <= Math.Max(p1.first, p2.first) && (p.first >= Math.Min(p1.first, p2.first))) && (p.second <= Math.Max(p1.second, p2.second) && (p.second >= Math.Min(p1.second, p2.second)))) return 1; } return 0;} // Function to check if tower// of sight issue occurredstatic void towerOfSight(pair a, pair b, pair c, pair d){ int flag = 0; if (checkIntersection(a, c, b) == 1) // B lies between AC flag = 1; else if (checkIntersection(a, c, d) == 1) // D lies between AC flag = 1; else if (checkIntersection(b, d, a) == 1) // A lies between BD flag = 1; else if (checkIntersection(b, d, c) == 1) // C lies between BD flag = 1; Console.Write(flag==1?"Yes\n":"No\n");} // Driver codepublic static void Main(String[] args){ // Point A pair a = new pair( 0, 0 ); // Point B pair b = new pair( 0, -2 ); // Point C pair c = new pair( 2, 0 ); // Point D pair d = new pair( 0, 2 ); towerOfSight(a, b, c, d); }}// This code is contributed by Princi Singh |
Javascript
<script>// Javascript program to check if tower// of sight issue occurs or not// Function to check if point p lies in// between the line joining p1 and p2function checkIntersection(p1,p2,p){ let val; // If parallel to X-axis if (p1[1] == p2[1] && p1[1] == p[1]) { if (p[0] <= Math.max(p1[0], p2[0]) && (p[0] >= Math.min(p1[0], p2[0]))) // Point p lies between p1 and p2 return 1; } // If parallel to Y-axis if (p1[0] == p2[0] && p1[0] == p[0]) { if (p[1] <= Math.max(p1[1], p2[1]) && (p[1] >= Math.min(p1[1], p2[1]))) // Point p lies between p1 and p2 return 1; } // If point p satisfies the equation // of line joining p1 and p2 else { val = (p[1] - p1[1]) * (p2[0] - p1[0]) - (p[0] - p1[0]) * (p2[1] - p1[1]); if (val == 0) if ((p[0] <= Math.max(p1[0], p2[0]) && (p[0] >= Math.min(p1[0], p2[0]))) && (p[1] <= Math.max(p1[1], p2[1]) && (p[1] >= Math.min(p1[1], p2[1])))) return 1; } return 0;}// Function to check if tower// of sight issue occurredfunction towerOfSight(a,b,c,d){ let flag = 0; if (checkIntersection(a, c, b) == 1) // B lies between AC flag = 1; else if (checkIntersection(a, c, d) == 1) // D lies between AC flag = 1; else if (checkIntersection(b, d, a) == 1) // A lies between BD flag = 1; else if (checkIntersection(b, d, c) == 1) // C lies between BD flag = 1; document.write(flag==1?"Yes\n":"No\n");}// Driver code// Point Alet a=[0,0];// Point Blet b=[0, -2 ];// Point Clet c=[2, 0 ];// Point Dlet d=[0, 2];towerOfSight(a, b, c, d);// This code is contributed by avanitrachhadiya2155</script> |
Output:
Yes
Time Complexity: O(1)
Auxiliary Space: O(1)
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