Javascript Program for Sort the given matrix

0 0 2 minutes read

Given a n x n matrix. The problem is to sort the given matrix in strict order. Here strict order means that matrix is sorted in a way such that all elements in a row are sorted in increasing order and for row ‘i’, where 1 <= i <= n-1, first element of row ‘i’ is greater than or equal to the last element of row ‘i-1’.
Examples:

Input : mat[][] = { {5, 4, 7},
                    {1, 3, 8},
                    {2, 9, 6} }
Output : 1 2 3
         4 5 6
         7 8 9

Approach: Create a temp[] array of size n^2. Starting with the first row one by one copy the elements of the given matrix into temp[]. Sort temp[]. Now one by one copy the elements of temp[] back to the given matrix.

Javascript

<script> 
  
// JavaScript implementation to sort 
// the given matrix 
  
let SIZE  = 10 
  
// function to sort the given matrix 
function sortMat(mat, n) 
{ 
    // temporary matrix of size n^2 
    let temp = new Array(n * n); 
    let k = 0; 
  
    // copy the elements of matrix one by one 
    // into temp[] 
    for (let i = 0; i < n; i++) 
        for (let j = 0; j < n; j++) 
            temp[k++] = mat[i][j]; 
  
    // sort temp[] 
    temp.sort(); 
      
    // copy the elements of temp[] one by one 
    // in mat[][] 
    k = 0; 
    for (let i = 0; i < n; i++) 
        for (let j = 0; j < n; j++) 
            mat[i][j] = temp[k++]; 
} 
  
// function to print the given matrix 
function printMat(mat, n) 
{ 
    for (let i = 0; i < n; i++) { 
        for (let j = 0; j < n; j++) 
            document.write( mat[i][j] + " "); 
        document.write( "<br>"); 
    } 
} 
  
// Driver program to test above 
  
    let mat = [ [ 5, 4, 7 ], 
                 [ 1, 3, 8 ], 
                [ 2, 9, 6 ] ]; 
    let n = 3; 
  
    document.write( "Original Matrix: " + "<br>"); 
    printMat(mat, n); 
  
    sortMat(mat, n); 
    document.write( "<br>"); 
    document.write( " 
Matrix After Sorting: " + "<br>"); 
    printMat(mat, n); 
  
// This code is contributed by Manoj 
  
</script> 

Output:

Original Matrix:
5 4 7
1 3 8
2 9 6

Matrix After Sorting:
1 2 3
4 5 6
7 8 9

Time Complexity: O(n²log₂n).
Auxiliary Space: O(n²).

Please refer complete article on Sort the given matrix for more details!

Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 zambiatek!